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5 questions with no upvoted or accepted answers
2 votes
0 answers
150 views

Evaluate this product $n \times \frac{n-1}{2} \times \dots \times \frac{n-(2^k-1)}{2^k}$

For $k = \lfloor \log_{2}(n+1) \rfloor - 1$ evaluate $n \times \frac{n-1}{2} \times\frac{n-3}{4} \times \frac{n-7}{8} \times \dots \times \frac{n-(2^{k}-1)}{2^k}$ So the product goes up to $k$ and I ...
Lewis's user avatar
  • 69
1 vote
1 answer
45 views

Sum and product problem

How can I find the result of: $\sum\limits_{i=1}^{n}\prod\limits_{j=1}^{2} ij$ I know that $\prod\limits_{j=1}^{2} ij = 2i^2$, so I should simply do the summation as $\sum\limits_{i=1}^n2i^2$?
Maria Giulia Martins's user avatar
1 vote
0 answers
48 views

Transforming a long sum of products for efficient computation (based on spanning trees in a complete graph)

Let's say there is a set of $n$ real coefficients: $a_1,...,a_n$. My task is to calculate the value of a rather simple sum of k products: ...
maciek's user avatar
  • 239
1 vote
0 answers
35 views

Help with simplification of this expression.

So i have derived this expression and would like to simplify it (i.e find an expression purely in terms of J and v). $$ J\bigg[1+\sum_{n=1}^{J-1}\prod_{k=1}^{n}\frac{k(1-v)(J-k)}{(k+1)(J-k-1 + vk)}\...
vilacelestin's user avatar
0 votes
0 answers
45 views

Inequality with Products and Sums

I need help to find a proof for the following inquality. Assuming that $ 0 \leq c_i \leq 1 $ and $ 0 \leq d_i \leq 1 $, show that $$ \prod_{i=1}^N (c_i + d_i - c_i d_i) \geq \prod_{i=1}^N c_i + \prod_{...
Duns's user avatar
  • 778