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3 votes
1 answer
73 views

Whether the given function is one-one or onto or bijective?

Let $f:\mathbb{R}\to \mathbb{R}$ be such that $$f(x)=x^3+x^2+x+\{x\}$$ where $\{x\}$ denotes the fractional part of $x$. Whether $f$ is one-one or onto or both? For one-one, we need to show that if $f(...
PAMG's user avatar
  • 4,500
1 vote
2 answers
119 views

Show that a function is $f$ bijective if $f(f(f(2x+3)))=x$ for all real $x$

Let $ f : \mathbb{R} \to \mathbb{R} $ is a function such that $$ \forall x\in\mathbb{R} : f(f(f(2x+3)))=x $$ Show that $f$ is bijective. We have to show that $f$ is injective and surjective. How do we ...
Trifon's user avatar
  • 113
0 votes
1 answer
46 views

How can I study the changes of $f_k(x)=\frac{e^{kx}-1}{2e^x}$

Let $f_k(x)$ be a function defined on $\mathbb{R}$ by $$f_k(x)=\frac{e^{kx}-1}{2e^x}$$ Where $k$ is a real , How can I study according to the values of $k$ the changes of the changes of $f_k$ I ...
Mostafa dd's user avatar
-3 votes
1 answer
100 views

Is this an injection from $\mathbb{R}_+$ to $(0,1)$? [closed]

I am wondering if $f: \mathbb{R}_+ \rightarrow (0,1)$ is an injection if $f$ just moves the decimal point to the left of each number an equal amount of times as how far the decimal point is from the ...
Princess Mia's user avatar
  • 2,979
0 votes
1 answer
26 views

Is it possible for a function to be continuously derivable over its entire open domain except for a removable discontinuity?

For example, is there a function $f \in \mathcal{C}(\mathbb{R}) \cap \mathcal{C}^1(\mathbb{R} \setminus \{ 0 \})$ such that $$ \exists \lim_{x \to 0} f'(x) = \lim_{x \to 0} \lim_{y \to x} \frac{f(y)-f(...
Juan's user avatar
  • 33
2 votes
2 answers
59 views

Is there a 'simple' function that flips the order of positive numbers without making them negative?

If I want to flip the order of some numbers, I can just multiply them with -1. But is there a not too complicated way to do it such that the numbers remain positive? Here's my attempt to word the ...
proof-of-correctness's user avatar
7 votes
2 answers
548 views

Find all functions $f:\mathbb{R}\rightarrow\mathbb{R}$ where $f(xf(y)+f(x)+y)=xy+f(x)+f(y)$

Find all functions $f:\mathbb{R}\rightarrow\mathbb{R}$ for two real numbers $x$ and $y$ where $f(xf(y)+f(x)+y)=xy+f(x)+f(y)$ For $x=0$ and $y=-f(0)$ then $f(-f(0))=0$. So, there is a real root $r_0$ ...
Farshid Farhat's user avatar
0 votes
1 answer
30 views

Finding domain and range without equation

We are given that $f(x)$ has domain $x \geq -4$ and $f(x) < -1$. All numbers in $\mathbb{R}$. Now we want to find the domain of $3f(x+1)+4$. My solution is $x+1 \geq -4$ so new domain is $x \geq -5$...
Salazar_3854708's user avatar
0 votes
1 answer
108 views

Show that $f(rx)=(f(x))^r$ for all $r\in \mathbb{Q}$ if $f(x+y)=f(x).f(y)$ for all $x,y\in \mathbb{R}$

$f:\mathbb{R}\to \mathbb{R}$ be function satisfying $f(x+y)=f(x).f(y)$ for all $x,y\in \mathbb{R}$ and $lim_{x\to 0} f(x)=1$ then show that $f(rx)=(f(x))^r$ for all $r\in \mathbb{Q}$. Here is what I ...
Shivam M's user avatar
  • 322
0 votes
0 answers
124 views

Converse of Bolzano Weierstrass Theorem

Bolzano Weierstrass Theorem (for sequences) states that Every bounded sequence has a limit point. However the converse is not true i.e. there do exist unbounded sequence(s) having only one real limit ...
Raminder Singh's user avatar
6 votes
4 answers
1k views

Why is the range a larger set than the domain?

When we have a function $f: \mathbb{R} \to \mathbb{R}$, I can intuitively picture that and think that for every $x \in \mathbb{R}$, we can find a $y \in \mathbb{R}$ such that our function $f$ maps $x$ ...
nocomment's user avatar
  • 319
0 votes
0 answers
38 views

Finding Sequence of Polynomials Whose Existence is Guaranteed

I'm interested in knowing whether we can find a sequence of polynomials (thanks to Stone-Weierstras) that converges to the Weierstrass function on some random interval (for instance, [-2 , 2]. The ...
Federico's user avatar
0 votes
2 answers
74 views

Nowhere continuous functions $f: \mathbb{R} \to \mathbb{R}$ such that $f(f(x)) = (f(x))^2$

Are there any nowhere continuous functions $f: \mathbb{R} \to \mathbb{R}$ satisfying the identity $f(f(x)) = (f(x))^2$ $\forall x \in \mathbb{R}$?
Rick Does Math's user avatar
6 votes
2 answers
367 views

How to strengthen $ h \big( 2 h ( x ) \big) = h ( x ) + x $ to force $ h $ to be linear?

Let $ h : \mathbb R \to \mathbb R $ be an injective function such that $$ h \big( 2 h ( x ) \big) = h ( x ) + x $$ for all $ x \in \mathbb R $, and $ h ( 0 ) = 0 $. What would be an as mild as ...
Redundant Aunt's user avatar
0 votes
1 answer
41 views

What is the correct inverse function for $f(x) = x^2$. Question about terminology.

Is the inverse function $g_1(x)=\sqrt{x}$ or is it $g_2(x)=-\sqrt{x}$. With what terminology can we describe both of these functions?
VLC's user avatar
  • 2,527

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