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3 votes
0 answers
107 views

Proof that for all nonzero real numbers $a$, $\frac{1}{a}$ is nonzero

I was wondering if someone could check my proof that "For all $a\in\mathbb{R}$, if $a\neq 0$ then $\frac{1}{a}\neq 0$". The definitions/assumptions I am basing the proof off of come from &...
user1320946's user avatar
-4 votes
2 answers
124 views

How can the reals be the set of all points on a number line when there exist non-constructible reals? [closed]

We are given the intuition that the reals form all the numbers on the numberline. However, this intuition wasn't working for me as the existence of non-constructible reals seems to me to imply that ...
Princess Mia's user avatar
  • 2,979
0 votes
1 answer
80 views

Characterizations of the reals

I know that one characterization of the reals is that it is the only Dedekind-complete ordered field. Are there any other characterizations of the reals as a field?
mathlander's user avatar
  • 4,057
1 vote
0 answers
67 views

What's the proof that the only Dedekind-complete field is the reals? [duplicate]

I know that the field of the rational numbers is ordered but not Dedekind-complete. What's the proof that the only Dedekind-complete field is the reals?
mathlander's user avatar
  • 4,057
0 votes
1 answer
748 views

Prove that real multiplication distributes over addition

The distributive property of real numbers states that $“$for all $a, b, c \in \mathbb{R}$, we've $a⋅(b + c) = a⋅b + a⋅c$ and $(b + c)⋅a = b⋅a + c⋅a”$. How to prove this field property of real numbers? ...
user avatar
0 votes
2 answers
44 views

Proving a set X is dense in [0,1] equivalence relation [duplicate]

Let the relation in $\mathbb{R}: x \equiv y \ \mbox{mod} \ \mathbb{Z}$, when $x-y \in \mathbb{Z}$. For each $n \in \mathbb{N}$, let $x_n \in [0,1)$ such that $x_n \equiv \sqrt{n} \ \mbox{mod} \ \...
Víctor Elías Anhuamán Córdova's user avatar
6 votes
2 answers
118 views

Two "different" definitions of $\sqrt{2}$

In Walter Rudin's Principles of Mathematical Analysis (3rd edition) (page 10), it is proved that for every $x>0$ and every integer $n>0$ there is one and only one positive real $y$ such that ...
user avatar
-2 votes
1 answer
48 views

Construct a sequence in A that converges to the supremum of A [closed]

It is similar to this question that I learned quite a bit from: Showing the set with a $\sup$ has a convergent sequence But I want to ask how can I construct an example of (Sn). i.e. If A is a ...
Neezo's user avatar
  • 3
0 votes
2 answers
71 views

Proving $x^{r} \cdot x^{s} = x^{r + s}$ provided two facts

I have the following two facts: For positive numbers $a$ and $b$ and natural numbers $n$ and $m$, we have $a = b$ if and only if $a^{n} = b^{n}$ if and only if $a^{1/m} = b^{1/m}$. For a ...
user avatar
1 vote
2 answers
267 views

real numbers of the form $\frac{m}{10^n} $ with $m,n \in \mathbb{Z} $ and $n \geq 0$ is dense in $\mathbb{R}$ . [duplicate]

Problem : Verify if the statement if true of false - The set $S$ of all real numbers of the form $\frac{m}{10^n} $ with $m,n \in \mathbb{Z} $ and $n \geq 0$ is dense in $\mathbb{R}$ . I think this ...
Suman Kundu's user avatar
  • 2,208
2 votes
1 answer
449 views

Question on the archimedean property

Let $a,b \in \Bbb ℝ$. Suppose that $a>0$. Prove that there is some $n\in \Bbb N$ such that $b\in[-na, na]$. I understand how the Archimedean Property can be used to prove this statement if $b$ is ...
user145551's user avatar
1 vote
3 answers
2k views

Arithmetic Operations with Infinities in Real Analysis

Infinity is not a number , thus we cannot perform the usual arithmetic operations that we do with real numbers This is the usual reason given when asked why we can't perform the usual arithmetic ...
Perturbative's user avatar
  • 13.2k
6 votes
2 answers
392 views

Path From Positive Dedekind Cuts to Reals?

Don't spend a lot of time on this. I'm certain I could bang it out myself; but maybe there's an answer out there that someone already knows. Say we use Dedekind cuts to construct the reals. Addition ...
David C. Ullrich's user avatar
3 votes
1 answer
180 views

Dedekind's Cuts Lemma

I'm studying Dedekind's Cuts and his construction of Real numbers from the Rational ones. Here we are allowed to use $\Bbb{Q}$ as an ordered field and all all its properties (Archimedean Property, his ...
Derso's user avatar
  • 2,811
0 votes
1 answer
70 views

Related Zorn's lemma proof?

Let $S$ be a partially ordered set, with the additional property that every chain $s_0\le s_1 \le s_2 \le...$ has an upper bound in $S$ (i.e. there is some $t$ in $S$ such that $s_n \le t$ for all $n$)...
Mark's user avatar
  • 27