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3 votes
1 answer
177 views

Suppose $A$ is a countable subset of $\mathbb{R}$. Show that $\mathbb{R} \sim \mathbb{R} \setminus A $.

Here is the question I am trying to answer: Let $\mathbb{R}$ denote the reals and suppose A is a countable subset of $\mathbb{R}$. Show that $\mathbb{R} \sim \mathbb{R} \setminus A $. My attempt: ...
eulersnumber's user avatar
3 votes
1 answer
109 views

Is the order inevitable in constructing the real numbers?

There are several ways to construct real numbers, such as the Dedekind cut, monotone bounded sequences and Cauchy sequences. It is obvious that the former two involves the order of the rational ...
Eric's user avatar
  • 4,527
3 votes
1 answer
69 views

$\text{ Proving }\; A \subseteq \Bbb R \text{ A is bounded above} \Rightarrow A^c \text{ is not?} $

Prove: Let $A \subseteq \Bbb R$. Prove that if $A$ is bounded above, then $A^c$, the complement of $A$ is not bounded above. $ A^c = $ those element of the universe that are not in A. $ \Bbb R =$ ...
Jon's user avatar
  • 1,916
3 votes
1 answer
46 views

Distance of a real number to a discrete set of scaled sine values

Let $M>0$ be an integer, $c\in(0,\frac{1}{2})$ a real number, $$ a_{m,n}:=\frac{2n}{\pi}\sin\frac{m\pi}{2n}, $$ $$ A_n:=\left\{a_{m,n}:~m=1,\ldots,n-1\right\}, \text{ and} $$ $$ d_n:=\operatorname{...
Hui Zhang's user avatar
  • 596
3 votes
1 answer
121 views

Who will win in this choosing nested intervals game? (a.k.a. Banach–Mazur game)

Question Alice and Bob are playing a game. The rules are as follows: First Alice chooses a compact interval $A_1\subset\mathbb R$ (in this question, intervals contain more than one points, they are ...
Feng's user avatar
  • 13.7k
3 votes
1 answer
59 views

Extraction of pointwise convergenct subsequence using Arzela-Ascoli theorem

Let $f_n:[a, b] \rightarrow \mathbb{R}$ be a sequence of continuous functions which is uniformly bounded i.e. $||f_n||_{L^{\infty}} \leq M <\infty$ and satisfies $f_n(a)=A$ for all $n\in \mathbb{N}....
Celestina's user avatar
  • 1,174
3 votes
1 answer
620 views

Are these valid Dedekind cuts for $e$ and $\pi$?

I took the liberty to attempt to construct Dedekind cuts for $e$ and $\pi.$ That is, come up with a set $\alpha$ of rational numbers (that would correspond to the reals $e$ and $\pi$) such that, If $...
Markus Klyver's user avatar
2 votes
5 answers
3k views

Direct proof of Archimedean Property (not by contradiction)

I looked at the proof of Archimedean Property in several places and, in all of them, it is proven using the following structure (proof by contradiction), without much variation: If $\space x \in \...
Vinicius ACP's user avatar
2 votes
1 answer
3k views

Showing any real number between 0 and 1 has a unique binary expansions

Hello I have tried to prove this result as I know it is true, it is obvious but I dont know how. Ive thought of dividing the interval into two pieces and checking which side the number is on, and then ...
user avatar
2 votes
2 answers
184 views

Finding an irrational number between two given irrational numbers constructively

Statement: Let $$X=\{(a,b) \in \mathbb{R} \setminus \mathbb{Q} \times \mathbb{R} \setminus \mathbb{Q}:a<b\}$$ There exists a function $f:X \rightarrow \mathbb{R} \setminus \mathbb{Q}$ such that for ...
Mohammad tahmasbi zade's user avatar
2 votes
3 answers
353 views

A positive real number $x$ with the property $x^3=3$ is irrational.

I have the following problems: 1) There exists a positive real number $x$ such that $x^3=3$. 2) A positive real number $x$ with the property $x^3=3$ is irrational. My Idea for 1) would be (there ...
MatheSt's user avatar
  • 97
2 votes
3 answers
139 views

$|a-b|<\varepsilon\implies a=b$ for uniqueness of limit?

Consider the following statement: Let $a,b\in\mathbb{R}$ be any two real numbers. Then we have that $$\forall\varepsilon>0:|a-b|<\varepsilon\implies a=b.$$ Here is my attempt to prove it: Proof. ...
mahlovic's user avatar
2 votes
4 answers
743 views

How tounderstand the proof to show if a real number $w>0$ and a real number $b>1$, $b^w>1$?

Claim: If there are two real numbers $w>0$ and $b>1$, then $b^w>1$. One proof is that for any rational number $0<r<w$ and $r=m/n$ with $m,n\in\mathbb Z$ and $n\ne0$, $(b^m)^{1/n}>1$...
Drake Marquis's user avatar
2 votes
1 answer
671 views

Prove that the following set is dense in R

I need to show $ S = { m\cdot \sqrt{2}+ n\cdot \sqrt{3},where~m,~n~in~\mathbb{Z}} $ is dense in $\mathbb{R}$. I showed that S has an element in $(0,ε)$ for every $ε>0.$ How do I proceed to show ...
ntarki's user avatar
  • 163
2 votes
1 answer
135 views

Set of finite sums is dense

Let $(a_n)_{n\geq 1}$ be a sequence of non-negative real numbers such that $a_n \to 0$ but $\sum_{n\geq 1} a_n$ diverges. Show that the set of sums $\sum_{n \in S} a_n$, where $S$ ranges over the ...
DesmondMiles's user avatar
  • 2,813

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