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-1 votes
1 answer
2k views

Expectation of a quotient of random variables

Let $Y$ follow the distribution described by the PDFs $f_Y(y)=2y$ on $(0,1)$. Conditionally on $Y=y$, $X$ follows a uniform distribution on $(0,y)$. Compute $E(X)$ and $E(X/Y)$. I have calculated the ...
Pablo's user avatar
  • 682
-1 votes
1 answer
146 views

Question about orthogonality principle

Orthogonality principle states the following: let $V$ and $W$ be any random variables then for any function $f(W)$ \begin{align} E[(V-E[V|W])f(W)]=0 \end{align} My question is wether the following ...
Boby's user avatar
  • 6,015
-1 votes
1 answer
22 views

Can this random variable enter the conditional expectation? Why?

Let $\mathcal{F}_1\subseteq\mathcal{F}_2\subseteq\mathcal{F}_3$ be a filtration, and X, Y two random variables, where X and Y are both $\mathcal{F}_3$-measurable. Can the expression: $$\mathbb{E}[(X\...
Andrei's user avatar
  • 93
-1 votes
1 answer
47 views

Iteration of conditional expectation conditioned on independent random variables

This comes from Aad Van der Vaart - Asymptotic statistics, Lemma 11.11 (Hoeffding Decomposition) Suppose I have independent random variables $X_1,...,X_n$. For any random variables $T$ such that $\...
dante's user avatar
  • 353
-1 votes
1 answer
162 views

Find probability mass function and conditional expectation [closed]

Let $X_0,X_1,X_2,...$ be independent identically distributed nonnegative random variables having a continuous distribution. Let $N$ be the first index $k$ for which $X_k>X_0$. That is, $N=1$ if ...
Fullbright's user avatar
-1 votes
1 answer
817 views

Conditional expectation of the product of two dependent random variables

Let $A$, $B$ and $C$ be random variables, with $A$ and $B$ dependent. Is it true that $\mathbb{E}(A\cdot B|C)=\mathbb{E}(A|C)\cdot\mathbb{E}(B|A,C)$? In particular, can I say that \begin{equation*}\...
Poecilia's user avatar
  • 341
-1 votes
1 answer
47 views

Distribution of independent random variables [closed]

I have problem with the following: We have a random variable $X_1$, which is binomially distributed, i.e. $X_1$ ~ $B_{n,p}$. Furthermore $X_2$ is independent from $X_1$ and is binomially distributed ...
ducks17's user avatar
  • 657
-1 votes
2 answers
63 views

Conditional expectation calculation

Is following equality true: $$E[X_{1}X_{2}|X_{1}=2]=E[2X_{2}|X_{1}=2]$$ If no how to calculate/simplify this, assuming that we have joint density and marginal densities of those RV and they are not ...
mokebe's user avatar
  • 489
-2 votes
1 answer
111 views

Prove or disprove that if $X$ is independent of $Y$, then $E[X|F]$ is independent of $E[Y|F]$ [closed]

If $X$ is independent of $Y$, then $E[X|F]$ is independent of $E[Y|F]$. If the above statement is not correct, how to construct a counter example to disprove it?
John's user avatar
  • 13
-2 votes
1 answer
101 views

Conditional Expectation Counterexample [closed]

I am trying to think of a counterexample to the following: If $E(Y|X) =0$, and $E(Y^2|X) = \sigma ^2$, a constant, then $X$ and $Y$ are independent. Thanks for any help in advance.
shmiggens's user avatar
  • 505
-2 votes
1 answer
32 views

For the random variables X,Y and Z, Is the expression E[E[X|Z]|Y] = E[X|Z] true or False given we do not know if X,Y,Z are independent or not.

Given, we do not know if $X,Y,Z$ are independent or not. Will the expression $E[E[X|Z]|Y] = E[X|Z]$ hold true? What I have tried: Now, $E[X|Z]$ is a random variable so let $E[X|Z]$ be $A$ So, problem ...
Morde Kaiser's user avatar
-2 votes
1 answer
81 views

Law of iterated expectations applied to a ratio

Consider the random variables $Y, Z_1, Z\equiv(Z_1,\dots,Z_n)$ with $Z_1,...,Z_n$ i.i.d. Is it true that $$\mathbb E\left(\frac{Y}{Z_1}\right)=\mathbb E\left(\frac{\mathbb E(Y\mid Z)}{Z_1} \right)$$?...
Star's user avatar
  • 266
-2 votes
2 answers
36 views

$\mathbb E(X)=\sum \mathbb E(X\mid Y)\mathbb P(Y=n)$ ¿why?

Let $\langle X, Y\rangle$ be a random vector such that $X$ has finite expected value and $Y$ is discrete with values $​​0.1, \cdots $ such that $\mathbb P (Y = n)> 0$ for $n = 0.1, \cdots$ Show ...
user avatar
-2 votes
1 answer
66 views

Prove that E(E(Y|X)*X)=E(Y*X) [closed]

How can one prove that: $$ E( E(Y \mid X) \cdot X)=E(Y \cdot X)$$ if $E(Y \mid X)$ is well-defined. Are we free to use the law of iterated expectations? I am confused since now the expectation of ...
RAGMS's user avatar
  • 43
-2 votes
2 answers
323 views

When does the conditional expectation of the sum of random variables match with the sum their respective conditional expectations?

I am studying stochastic processes. While studying random walk I acquainted with a notation $N_i$ where $$N_i = \mathrm {Total\ number\ of\ times\ of\ visit\ to\ i}.$$ Let $(X_n)_{n \geq 0}$ be a ...
little o's user avatar
  • 4,862

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