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Sum of members from multiplicative group of prime order $k$ modulo prime $P$? $c$ in: $\sum_{n=1}^{k} (g^n \bmod P) = c \cdot P$ ($g$ prime order $k$)
Let $P$ be a prime ($>2$) and $g$ a value between $2$ and $P-2$.
Let $M$ be the set of numbers which can be generated with $g$:
$$M = \{g^n\bmod P, \text{ with } 0 < n <P \}$$
If $g$ is a ...
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