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3 votes
3 answers
388 views

$\operatorname{Li}_{2} \left(\frac{1}{e^{\pi}} \right)$ as a limit of a sum

Working on the same lines as This/This and This I got the following expression for the Dilogarithm $\operatorname{Li}_{2} \left(\frac{1}{e^{\pi}} \right)$: $$\operatorname{Li}_{2} \left(\frac{1}{e^{\...
Srini's user avatar
  • 862
7 votes
2 answers
132 views

Series expansion of $\text{Li}_3(1-x)$ at $x \sim 0$

My question is simple, but maybe hard to answer. I would like to have a series expansion for $\text{Li}_3 (1-x)$ at $x \sim 0$ in the following form: $$\text{Li}_3 (1-x) = \sum_{n=0} c_n x^n + \log x \...
Pxx's user avatar
  • 697
5 votes
2 answers
368 views

Closed form of the sum $s_4 = \sum_{n=1}^{\infty}(-1)^n \frac{H_{n}}{(2n+1)^4}$

I am interested to know if the following sum has a closed form $$s_4 = \sum_{n=1}^{\infty}(-1)^n \frac{H_{n}}{(2n+1)^4}\tag{1}$$ I stumbled on this question while studying a very useful book about ...
Dr. Wolfgang Hintze's user avatar
4 votes
1 answer
82 views

Evaluate the following series sum.

Problem I’m trying to evaluate the following series sum \begin{equation} S_{j}(z) = \sum_{k=1}^{\infty} \frac{2 H_{k} z^{k+2}}{(k+1)(k+2)^{j}} \end{equation} Where \begin{equation} H_{k} = \sum_{n=1}^{...
BB_'s user avatar
  • 87
1 vote
1 answer
59 views

Further Stirling number series resummation

\begin{equation} \sum_{m=1}^\infty\sum_{n=1}^\infty (-1)^{n } \frac{S_m^{(3)}}{m! n}(-1 + u)^{(m + n - 1)} (\frac{x}{-1 + x})^m \end{equation} Note: $S^{(3)}_m$ belongs to the Stirling number of the ...
YU MU's user avatar
  • 99
0 votes
0 answers
59 views

Stirling number series resummation

\begin{equation}\sum_{m=1}^{\infty}\frac{a_1^3 S_m^{(3)} (u-1)^{m-1} \left(\frac{x}{x-1}\right)^m}{m!}\end{equation} Does somebody know the result of this resummation? Note: $S_m^{(3)} $ belongs to ...
YU MU's user avatar
  • 99
0 votes
0 answers
82 views

General expression of a triangle sequence

\begin{gather*} \frac{1}{4} \\ \frac{1}{4} \quad \frac{1}{4} \\ \frac{11}{48} \quad \frac{1}{4} \quad \frac{11}{48} \\ \frac{5}{24} \quad \frac{11}{48} \quad \frac{11}{48} \quad \frac{5}{24} \\ \frac{...
YU MU's user avatar
  • 99
0 votes
1 answer
53 views

General expression of a (maybe 3 or 2 dim) sequence [closed]

$\frac{1}{2}$ $\frac{1}{4}$ $\frac{1}{2}$ $\frac{1}{6}$ $\frac{1}{4}$ $\frac{11}{24}$ $\frac{1}{8}$ $\frac{1}{6}$ $\frac{11}{48}$ $\frac{5}{12}$ $\frac{1}{10}$ $\frac{1}{8}$ $\frac{11}{...
YU MU's user avatar
  • 99
2 votes
0 answers
74 views

How can I prove that the following function is increasing in $x \in [0,1]$?

How can I prove that the following function is increasing in $x$: $$\sum_{i=1}^{\infty} x (1-x) ^ {i-1} \log \left (1+ \mu (1-x)^{i-1} \right)$$ where $\mu$ is any non-negative number and $x$ is in $[...
Patrik's user avatar
  • 21
16 votes
1 answer
551 views

Relations connecting values of the polylogarithm $\operatorname{Li}_n$ at rational points

The polylogarithm is defined by the series $$\operatorname{Li}_n(x)=\sum_{k=1}^\infty\frac{x^k}{k^n}.$$ There are relations connecting values of the polylogarithm at certain rational points in the ...
Vladimir Reshetnikov's user avatar