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12 votes
2 answers
718 views

General expressions for $\mathcal{L}(n)=\int_{0}^{\infty}\operatorname{Ci}(x)^n\text{d}x$

Define $$\operatorname{Ci}(x)=-\int_{x}^{ \infty} \frac{\cos(y)}{y}\text{d}y.$$ It is easy to show $$ \mathcal{L}(1)=\int_{0}^{\infty}\operatorname{Ci}(x)\text{d}x=0 $$ and $$\mathcal{L}(2)=\int_{0}^{\...
Setness Ramesory's user avatar
4 votes
3 answers
211 views

Does $\int_0^{2\pi}\frac{d\phi}{2\pi} \,\ln\left(\frac{\cos^2\phi}{C^2}\right)\,\ln\left(1-\frac{\cos^2\phi}{C^2}\right)$ have a closed form?

I am wondering if anyone has a nice way of approaching the following definite integral $\newcommand{\dilog}{\operatorname{Li}_2}$ $$\int_0^{2\pi}\frac{d\phi}{2\pi} \,\ln\left(\frac{\cos^2\phi}{C^2}\...
T-Ray's user avatar
  • 179
6 votes
2 answers
198 views

Computing closed-form of $\int_0^{\infty}\frac{\arctan x}{a^2x^2+1}\,dx$

Find the close form of the integral $$\int_0^{\infty}\frac{\arctan x}{a^{2}x^2+1}\,dx,\qquad a > 0.$$ I think this integral related with polylogarithm function. My attempt as follows: Let $$I(b)=\...
Kînan Jœd's user avatar
5 votes
5 answers
313 views

How can I compute this integral in closed form : $\int_0^{\frac{π}{4}}\ln^2(\tan x)dx$

How can I compute this integral in closed form : $$\displaystyle\int_{0}^{\displaystyle \tfrac{π}{4}}\ln^{2}\left(\tan x\right)dx$$ How can use Fourier series here ? $$-2\displaystyle \sum_{n=0}^{\...
user avatar
0 votes
0 answers
46 views

Evaluate a certain one-dimensional integral involving inverse trigonometric functions

Demonstrate that the integral of \begin{equation} \cos (y) \left(\sqrt{4-\sin ^2(y)} \cos ^{-1}(\sin (y))+4 \cos (y) \csc ^{-1}(2 \csc (y))\right) \end{equation} over $y \in [0,\frac{\pi}{2}]$ ...
Paul B. Slater's user avatar
8 votes
3 answers
745 views

Prove $\int_{\frac{\pi}{20}}^{\frac{3\pi}{20}} \ln \tan x\,\,dx= - \frac{2G}{5}$

Context: This question asks to calculate a definite integral which turns out to be equal to $$\displaystyle 4 \, \text{Ti}_2\left( \tan \frac{3\pi}{20} \right) - 4 \, \text{Ti}_2\left( \tan \frac{\pi}{...
Noam Shalev - nospoon's user avatar