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1 vote
0 answers
35 views

Why is the material conditional treated like logical entailment in second order quantification? [closed]

According to this Wikipedia article the second order axiom of induction is: $$\forall P(P(0)\land \forall k(P(k) \to P(k+1)) \to \forall x(N(x) \to P(x))$$ Where N(x) means x is a natural number. That ...
Electro-blob's user avatar
0 votes
0 answers
30 views

Question about the Peano axioms + linear order axioms

The signature consists of $S$, $0$ & $<$ and the axioms are: I - $\forall x (S(x) \not= 0)$ II - $\forall x \forall y (S(x) = S(y) \to x = y)$ III - First-order Induction schema IV - $<$ is ...
Hussein Aiman's user avatar
-2 votes
1 answer
53 views

Contradiction and Godel's incompleteness theorems

If T is a recursively axiomatizable formal system containing peano arithmetic and is able to carry out the proof for the Godel's incompleteness theorems (so according to Wikipedia includes primitive ...
Nikolai riber skånstrøm's user avatar
1 vote
1 answer
161 views

Understanding the Arithmetical Hierarchy

I am trying to get acquainted with the arithmetical hierarchy, and as I wrote down some examples, I got a bit confused. Consider the language $L=\{+\cdot,<,=,0,1\}$ of $\mathsf{PA}$. For example, ...
John's user avatar
  • 4,432
2 votes
1 answer
72 views

Is there a problem if I don't use $0$ in Peano arithmetic?

Peano arithmetic is the following list of axioms (along with the usual axioms of equality) plus induction schema. $\forall x \ (0 \neq S ( x ))$ $\forall x, y \ (S( x ) = S( y ) \Rightarrow x = y)$ ...
MathMan's user avatar
  • 103
1 vote
1 answer
144 views

Infinite statements from finite axioms

I want to know if a given finite subset of axioms of PA1 ( 1st order peano arithmetic ) can prove infinite sentences in PA1 such that those proofs need no other axioms except those in the given finite ...
jason's user avatar
  • 1
0 votes
1 answer
113 views

is arithmetic finitely consistent? [duplicate]

Let's take PA1( First order axioms of peano arithmetic ) for example. From godel's 2nd incompleteness theorem, PA1 can't prove its own consistency, more specifically it can't prove that the largest ...
jason's user avatar
  • 1
1 vote
2 answers
70 views

Modern reference on PA degrees?

I'm currently trying to work my way around some papers from Jockush et al, and PA degrees come up frequently. I'd be interested in a modern reference/survey summarizing the main results on the subject,...
Robly18's user avatar
  • 461
6 votes
5 answers
2k views

Confusion about Löb's theorem [duplicate]

To quote wikipedia: Löb's theorem states that in any formal system that includes PA, for any formula P, if it is provable in PA that "if P is provable in PA then P is true", then P is ...
G. Bellaard's user avatar
0 votes
0 answers
59 views

Non recursive provably total functions

It is provable that every primitive recursive function is total in 1st order PA. Some non primitive recursive functions are also provably total in PA. Can we show that a function is totally provable ...
user avatar
0 votes
1 answer
47 views

Meaning of Provable recursiveness

Is there any difference between provably total function and provable recursiveness of a function in first order PA ? From provably total I mean that the totality of the function itself is provable in ...
user avatar
0 votes
0 answers
40 views

Proving the set of true expressions in a theory cannot be expressed in this theory

Suppose we have a first-order theory $T_C$ that includes a binary function $C$. $C$ is a bijection $\Sigma \to \mathbb{N}$ where $\Sigma$ is the alphabet of $T_C$. The function $C$ is defined as ...
ampersander's user avatar
3 votes
1 answer
108 views

On the consistency of satisfiable first order theories

Considering this question, we know that a first order theory that admits a model has to be consistent. A model for a theory $T$ in a language $\mathcal L$ is an interpretation of $\mathcal L$ in which ...
Spasoje Durovic's user avatar
1 vote
1 answer
83 views

Does the property $T\vdash Pvbl_T(\ulcorner \sigma \urcorner) \implies T\vdash \sigma$ apply to set theories?

I know from other posts that $PA\vdash Pvbl_{PA}(\ulcorner \sigma \urcorner ) \implies PA\vdash \sigma$ and this applies to other extensions/restrictions of PA as well. Does it also apply to set ...
Ari's user avatar
  • 855
3 votes
3 answers
195 views

If Goldbach's conjecture G is undecidable in PA, then can we prove $\mathbb N\models G$?

Suppose Goldbach's conjecture $G$ is undecidable in first-order Peano arithmetic, $\sf{PA}$. That would mean there are models in which $G$ is true and other in which it is false. But intuitively, this ...
WillG's user avatar
  • 6,672

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