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-1 votes
1 answer
27 views

Stability of Subspaces under a Linear Map in Direct Sum Decomposition

Consider the vector spaces $D_1$, $D_2$, $D$ and $X$ such that $D\subset X$ and $D=D_1\oplus D_2$. Furthermore, suppose that $L:X\longrightarrow D$ is a linear map such that $D_1$ is stable under $L$...
amine's user avatar
  • 87
0 votes
1 answer
47 views

We are interested in finding for which $\lambda$ the operator $A - \lambda I$ is not surjective.

We are in the space $X = C[1/2, b]$ for some $b < 1$. We are interested in finding for which $\lambda$ the operator $A - \lambda I$ is not surjective. The operator $A: X \to X$ is given as $(Af)(x) ...
user avatar
-2 votes
1 answer
117 views

Thus $MV - VM = V^2$. So the spectrum of $V^2$ is $\sigma(V^2) = (\sigma(V))^2=0$. Why??

I am curious if this statement holds (it doesn't make much sense to me, but it was written in solutions in this form): $\sigma(A)=0\implies\sigma(A^2)=(\sigma(A))^2=0.$ Can anybody explain to me why ...
user avatar
4 votes
1 answer
72 views

Non-trivial closed maps on Banach spaces

Let's call a map closed if it takes any closed subset to a closed subset. I'm wondering if there are some "standard" examples of closed (in this sense) linear maps on a Banach space, other ...
geometricK's user avatar
  • 4,861
0 votes
1 answer
39 views

A bilinear operator is continuous iff verifying $|| \phi (v;w)|| \leq M ||v|| ||w|| $

First I know that this question has all ready be asked for exemple here but for bilinear operator with only one variable here I want to show it for linear operator with two variables. Question: Prove ...
OffHakhol's user avatar
  • 719
0 votes
0 answers
37 views

Adjoint of an operator on scaled Euclidean spaces

For $N\in \mathbb N$, equip $\mathbb C^N$ with the inner product $\langle\mathbf x,\mathbf y\rangle_N := N^{-1}\sum_i \overline x_i y_i$. Let $A$ be an $N\times M$ complex matrix. As an linear ...
AdamNie's user avatar
3 votes
2 answers
221 views

Every bounded linear operator is an infinitesimal generator

I'm studying the theory of semigroups from Pazy's book. I'm struggling to understand a specific inequality in the proof of a theorem stating that every bounded linear operator is an infinitesimal ...
mathematico's user avatar
1 vote
0 answers
25 views

Is the dual of a unitary operator on a Hilbert space always a continous linear operator?

I have encountered this in a course (not functional analysis), but I am wondering whether this is a general fact. Thank you very much in advance for any input!
J.R.'s user avatar
  • 481
1 vote
0 answers
42 views

A question about Composition Operators

Let $(X, \mathcal{B}, \mu)$ be a $\sigma$-finite measure space and $f:X\to X$ be a transformation such that $f(B)\in\mathcal{B}$ and $f^{-1}(B)\in \mathcal{B}$ for every $B\in\mathcal{B}$. Also there ...
user479859's user avatar
  • 1,297
1 vote
2 answers
212 views

Prove or disprove that Every bounded linear functional on a Banach space is a quotient map?

Prove or disprove that Every bounded linear functional on a Banach space is a quotient map? Let $X$ be a Banach space over $\mathbb{K}$ and $f:X\to \mathbb{K}$ be a functional on $X$. If $f$ is ...
Jana's user avatar
  • 475
0 votes
1 answer
32 views

Moving a constant operator inside an operator valued integral: Why $A\int_{X}f(t)B(t)dt=\int_Xf(t)AB(t)dt, f:X\to\mathbb{C},A,B$ linear operators

Let $X$ be some non-empty set and $\mathcal{H}$ be a Hilbert space over the complex numbers. Suppose that $A\in \mathcal{B}(H)$ is some fixed bounded operator and $B(t)\in\mathcal{B}(H),t\in\mathbb{R}$...
Epsilon Away's user avatar
  • 1,030
0 votes
1 answer
53 views

$\lim_{n}||T_n||\not\to 0\implies\sum_{n=0}^\infty T_n$ cannot converge in operator norm topology for self-adjoint $T_n\in\mathcal{B}(\mathcal{H})$

Let $\mathcal{H}$ be a Hilbert space and $\{T_n\}$ be a sequence of self-adjoint bounded linear operators. Take $T:=\sum_{n=0}^\infty T_n$ for now just as an assignment without worrying whether the ...
Cartesian Bear's user avatar
0 votes
2 answers
231 views

Connection between invariant subspaces and eigenvectors of a linear operator: Showing that if $A,B$ commute then $A$ and $B$ share an eigenvector [duplicate]

I got stuck trying to show that if $A,B$ are two linear operators on a finite dimensional vector space $V$ over the field $\mathbb{F}$, then $A$ and $B$ share an eigenvector. Quick Googling revealed ...
Cartesian Bear's user avatar
2 votes
2 answers
74 views

Does $x^T T(y) = y^T T(x)$ imply that $T$ is a linear operator?

Let $T:\mathbb{R}^n \rightarrow \mathbb{R}^n$ an operator satysfying: \begin{equation} x^T T(y) = y^T T(x) ~~~~\forall (x,y)\in \mathbb{R}^n\times \mathbb{R}^n. \end{equation} Does it imply that $T$ ...
Niz's user avatar
  • 87
0 votes
1 answer
55 views

Linearity of infinite dimensional matrix

The operator $T: \ell^2 \to \ell^2$ is given by the infinite-dimensional matrix with matrix elements \begin{align*} t_{kl} = \frac{\vert k - l \vert}{k^2l^2} \end{align*} for all $k, l \in \mathbb{N}...
Matthew Neil's user avatar

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