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Questions tagged [octonions]

For questions on the octonions, a normed division algebra over the real numbers. It is a non-associative higher-dimensional analogue in the hierarchy of real, complex, and quaternionic numbers.

4 votes
1 answer
72 views

Projective plane over the octonions (Cayley plane)

You can use octonion algebra's $\mathbb{O}$ over a field to coordinatize projective planes. They are called Cayley planes as far as I know. You can't use the usual approach with homogeneous ...
Vincent Batens's user avatar
0 votes
0 answers
101 views

Are all 12 possibilities for products of three octonions in fact possible?

The octonions are a non-associative, non-commutative, $8$-dimensional algebra over the reals. Consider a triple $(x,y,z)$ of three distinct octonions. There are $12$ possible products of those, such ...
user107952's user avatar
  • 21.4k
0 votes
1 answer
44 views

Sequence and Limit Definition at Quaternions

A sequence at $\mathbb{C}$ is a map $z_n: \mathbb{N} \to \mathbb{C}$, where $z_n$ converges to a $z_0 \in \mathbb{C}$ if: $$\forall \epsilon > 0, \text{ } \exists N \in \mathbb{N}; \text{ } \forall ...
Gabriel Fanini's user avatar
1 vote
1 answer
64 views

Square Root of a Arbitrary Octonion

Let $q = a + bi + cj + dk = a + Q \in \mathbb{H}$ a quaternion. So, we have: $$\sqrt{q} = \sqrt{\frac{|q| + a}{2}} + \frac{Q}{|Q|} \sqrt{\frac{|q| - a}{2}}$$ I have a question: this formula works for ...
Gabriel Fanini's user avatar
3 votes
0 answers
85 views

Closed form of product of sedenions

I'm a math student and I'm taking an algebra course. The professor introduced us to the field of quaternions ($\mathbb{Q}$), I became very curious about the topic and I saw that in addition to ...
Efesto's user avatar
  • 1
2 votes
1 answer
152 views

Some basics on octonions and quaternions

There is an $\mathbb{R}$-bilinear operation on the octonions $\mathbb{O} \otimes_{\mathbb{R}} \mathbb{O} \rightarrow \mathbb{O}$, which is not associative. My question is instead about the algebra ...
user avatar
4 votes
1 answer
214 views

Have generalisations of dual numbers/complex numbers/quaternions/octonions... been studied?

Can anyone point me to any generalisations of the notions in the title? For example say you have: $$ (a_1, a_2, a_3, ...,a_n) \in \mathbb{R}^n $$ and $$ \gamma_1, \gamma_2, \gamma_3, ..., \gamma_n $$ ...
realreal's user avatar
  • 139
3 votes
0 answers
90 views

Is there any practical use for octonions? [closed]

Quaternions are useful for describing orientation/ rotations in 3- dimensions, however is there much practical use for an 8-dimensional base hyper complex number id est Octonions?
Olly Doe's user avatar
7 votes
2 answers
245 views

Where the tensor used in the definition of the octonion product come from?

The octonion multiplication table is hard to remember. It's also not uniquely defined, but I'm assuming the definition that Wikipedia chose is fairly standard. One of the presentations uses an ...
Greg Nisbet's user avatar
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6 votes
3 answers
356 views

Are there an endless number of imaginary square roots for negative one?

When i learned about imaginary numbers, I learned that i represents the square root of negative one, as does i's counterpart below zero, "-i." But then I learned the same is true of the ...
HRW's user avatar
  • 61
1 vote
1 answer
67 views

How do you find the 3rd roots of hypercomplex imaginary units?

In my instance I want to find the 3rd root of the octonion imaginary unit $e_4$. I am working on simplifying the octonion $$ o=5+2e_1 \sqrt[3]{e_4}+3e_2 \sqrt[3]{e_4}+2e_3 \sqrt[3]{e_4} $$ $$ =5+...
Silense's user avatar
  • 13
1 vote
0 answers
45 views

When is operator conformality preserved under addition and subtraction?

An operator $A$ on an $n$-dimensional real vector space is conformal in case $$ A^T A = \alpha I \qquad \text{for some} \qquad \alpha \ge 0 , $$ and $$ \mathrm{det} A \ge 0 . $$ Let $A$ and $B$ be two ...
Steve White's user avatar
81 votes
0 answers
1k views

Does the $32$-inator exist?

Background It is common popular-math knowledge that as we extend the real numbers to complex numbers, quaternions, octonions, sedenions, $32$-nions, etc. using the Cayley-Dickson construction, we lose ...
pregunton's user avatar
  • 5,961
2 votes
0 answers
131 views

Extension of Hopf Fibrations

The only hopf fibrations that exist are the first three listed here. $\require{AMScd}$ \begin{CD} S^3 @>S^1>> S^2 \end{CD} $\require{AMScd}$ \begin{CD} S^7 @>S^3>> S^4 \end{CD} $\...
Gurvir Singh's user avatar
3 votes
1 answer
223 views

Norm of the Sedenions

Let the Cayley-Dickson doubling of the octonions be called the sedenions. The sedenions are not a division algebra, because they contain zero divisors. The presence of zero divisors means that the ...
a196884's user avatar
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