Skip to main content

All Questions

2 votes
1 answer
41 views

The join of two set partitions in the refinement order

Let $X$ be a set. The set $\Pi_X$ of all partitions of $X$ is partially ordered via the refinement order, which is defined by $\alpha \leq \beta$ if and only if for each block $A\in \alpha$ there is a ...
azimut's user avatar
  • 23.1k
1 vote
1 answer
39 views

Properites of Lattices imply eachother.

Assume S is a finite poset. A lattice is a poset S such that S is bounded. ∀ x, y ∈ S there exists x ∧ y (existence of Meet/Infimum). ∀ x, y ∈ S there exists x ∨ y (existence of Join/Supremum). ...
Promillemops's user avatar
9 votes
1 answer
508 views

Can the supremum of an uncountable family of measures be replaced by the supremum over a countable subfamily?

Consider a measurable space $(X,\mathcal{A})$. Let $\mathcal{M}$ denote the family of all countably additive measures $\mu\colon \mathcal{A}\to [0,+\infty]$. This family can be made into a partially ...
Rafael's user avatar
  • 561
0 votes
1 answer
65 views

Clarifications needed in an exercise about semilattice and abelian monoids in Arbib and Manes' text

The following question is taken from Arrows, Structures and Functors the categorical imperative by Arbib and Manes Exercise: A $\textbf{semilattice}$ is a poset in which every finite subset has a ...
Seth's user avatar
  • 3,683
3 votes
1 answer
116 views

Right unitor in the monoidal category of sup-lattices

In short: I am trying to find a right unitor for the monoidal category $\mathsf{SupLat}$ of sup-lattices. 1. Preliminaries Let $L,M$ be sup-lattices. Denote by $L^*$ the set $L$ with order $l \leq_{L^*...
Max Demirdilek's user avatar
1 vote
1 answer
107 views

Does $(f^{0})^{0} = f$ hold for suplattice homomorphisms?

Let $X$ and $Y$ be suplattices and $f: X \rightarrow Y$ a suplattice homomorphism (i.e. $f(\bigvee S)=\bigvee \{f(s)|s \in S\}$ for every subset $S \subseteq X$). Denote by $X^0$ and $Y^0$ the ...
Margaret's user avatar
  • 1,769
3 votes
1 answer
153 views

Why is product of infimum and supremum of a commuting pair of elements in a lattice-ordered group equal to the product of the elements?

Context: Self-study. Seth Warner's Modern Algebra (1965), question $15.11$ gives: If $(G, \circ \preccurlyeq)$ is a lattice-ordered group and if $x$ and $y$ are commuting elements of $G$, then $$\sup ...
Prime Mover's user avatar
  • 5,057
1 vote
1 answer
148 views

What is a relation of category of complete sublattices to category of lattices?

What is a relation of category of complete sublattices to category of lattices? I haven´t found much about a category of lattices, but I assume objects = lattices, morphisms = lattice homomorphisms. ...
Tereza Tizkova's user avatar
3 votes
2 answers
120 views

When does downward closure commute with supremum?

Let $A$ be a suplattices, and suppose we have a family $\{a_i\}_{i\in I}\subseteq A.$ Is $\bigcup_{i\in I}(\operatorname{\downarrow}a_i) = \operatorname{\downarrow} \sup_{i\in I}(a_i)$ in general? ...
Bumblebee's user avatar
  • 18.4k
0 votes
2 answers
131 views

What does being smaller that to a join means in a distributive lattice?

This is a follow up question to my previous question with more restrictions. It was answered negatively for arbitrary lattices, but mentioned that the result holds "only" in distributive ...
Bumblebee's user avatar
  • 18.4k
2 votes
1 answer
61 views

What does being smaller that to a join means in a lattice?

This sounds like a very naïve question, but I couldn't find a correct argument to prove/disprove it rigorously. Suppose we have a a subset $A$ of a lattice (or any join-semilattice), and some $x\le\...
Bumblebee's user avatar
  • 18.4k
1 vote
1 answer
114 views

$lub(a, b)$ and $glb(a, b)$ of non- comparable lattice elements

In an algebraic lattice $(L, \vee, \wedge, 0, 1)$, the binary operations $\vee$ and $\wedge$ are commutative and associative, satisfying absorption laws. The elements $0$ and $1$ are top and bottom ...
gete's user avatar
  • 1,352
1 vote
1 answer
110 views

Ordered set has a maximum and every subset has infimum $\implies$ every subset has supremum

Let $M$ be an ordered set such that $a)$ $M$ has a maximum element $b)$ Every (non-empty) subset of $M$ has an infimun. Prove that every non-empty subset of $M$ also has a supremum. I tried fixing a ...
PhantomR's user avatar
  • 342
2 votes
1 answer
103 views

About dense subalgebras of boolean algebras.

I started studying about Boolean algebras and got stuck doing an exercise. Maybe it's trivial but really I can't do it. First, a definition A subset $S$ of $B$, where $B$ is a Boolean algebra, is ...
Carlos Jiménez's user avatar
1 vote
1 answer
93 views

Understanding infimum in a complete lattice

For any two formal concepts, $(A_1,B_1)$ and $(A_2,B_2)$ of a formal context, the standard definition for the supremum and infimum in a complete lattice are as ...
Amrith Krishna's user avatar

15 30 50 per page