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0 votes
0 answers
22 views

If sub-universe $S$ of lattice has congruence $\theta$, does the lattice have a congruence $\lambda = \theta \cap S^2$? [duplicate]

Let $(L, \lor , \land )$ be a lattice and $S$ a sub-universe of the lattice. A sub-universe of a lattice will be any subset of the lattice set that is non-empty and closed under $\land$ and $\lor$. ...
lafinur's user avatar
  • 3,468
0 votes
0 answers
40 views

Understanding the definition of congruences over a lattice

Let $(L, \land, \lor)$ a lattice and $\theta$ a binary relation over $L$. We say $\theta$ is a congruence iff $$ x_0\theta x_1, y_0 \theta y_1 \Rightarrow (x_0 \lor y_0)\theta(x_1 \lor y_1) $$ (and ...
lafinur's user avatar
  • 3,468
0 votes
1 answer
45 views

Number of lattices over a finite set

I'm interested in finding a general formula for the number of lattices possible over a finite set $S$ as a function of the set's cardinality. For instance, how many lattices over $\{1, 2, 3\}$ are ...
lafinur's user avatar
  • 3,468
0 votes
1 answer
49 views

Help undsersanding matroid closure, loops, contraction and duality.

These ideas are being used a lot, but I cannot justify why they are correct: If M is a matroid and $T$ a subset of $E(M).$ Then $$(a)\ cl(T) = T \cup \{e \in E(M) - T: e \text{ is a loop of M/T}\}.$$ ...
Intuition's user avatar
  • 3,127
1 vote
1 answer
36 views

Infinite lattice with every totally ordered set finite

Construct a lattice L such that L is infinite but every totally ordered subset of L is finite? I really don't know how to proceed because i don't see how every totally ordered set would be finite ...
Sj2704's user avatar
  • 79
3 votes
3 answers
145 views

Are all complete lattices a pointed complete partial order, and vice versa?

A friend of mine asked for my help in drawing a venn diagram that includes the notions of partial orders (PO) in general, complete partial orders (CPO), pointed complete partial orders (CPPO), total ...
RandomMathDude's user avatar
0 votes
1 answer
159 views

Rigorously proving a lattice is sublattice of another

Consider the following two lattices, $L_1$ (top) and $L_2$ (bottom): I apologize for the bad image arrangement. We are asked whether $L_1$ is a sublattice of $L_2$. This can be visually observed ...
lafinur's user avatar
  • 3,468
1 vote
1 answer
194 views

For a distributive lattice, show $x ~\hat{\land}~ a = y ~\hat{\land}~ a$ and $x ~\hat{\lor}~ a = y ~\hat{\lor}~ a$ imply $x = y$.

Let $\hat{\land}, \hat{\lor}$ be binary operators denoting the infimum and supremum of two elements in a poset. I was given the following problem. For a distributive lattice $\langle ~L, ~\hat{\lor}~,...
lafinur's user avatar
  • 3,468
0 votes
0 answers
47 views

Is the number of atoms in a finite lattice always less than or equal to the length of the lattice?

My attempt: Let $\{v_1, v_2,...,v_m\}$ is the set of atoms in a finite lattice L. Now the chain $0<v_1 \lt (v_1 \lor v_2) \lt (v_1 \lor v_2 \lor v_3) \lt...\lt (v_1\lor v_2 \lor ...\lor v_m) \leq I$...
Mehak Batra's user avatar
2 votes
1 answer
155 views

Sublattice of an Atomic Lattice [closed]

Is the sublattice of an atomic lattice atomic? If not, then what additional condition is necessary for a sublattice to be atomic?
Mehak Batra's user avatar
3 votes
1 answer
165 views

Dual definition for distributivity lattice conditions

I am starting discrete mathematics and it came to me that distributive lattices has 2 equicalent representations for their definition: $a\wedge (b\vee c) = (a \wedge b)\vee (a\wedge c)$ $a\vee (b\...
Mateus Lima Silveira's user avatar
0 votes
0 answers
30 views

If $(f, g)$ is a Galois connection between two bounded lattices, then if $T$ is an ideal we have $f^{-1}(T)$ is an ideal

Let $\mathcal{I}(L)\:$ and $\mathcal{I}(N)\:$ be the ideal lattices of the bounded lattices $L$ and $N$ and let $(f, g)$ be a Galois connection between $L$ and $N$, then show that $\:\forall \:\: T \...
AleVanDerBauch's user avatar
1 vote
1 answer
330 views

Is a finite lattice where each element has exactly one complement distributive? Why or why not?

While reading the paper LATTICES WITH UNIQUE COMPLEMENTS by R. P. DILWORTH, I get to know that any number of weak additional restrictions are sufficient for a lattice with unique complement to be a ...
prime-ideal's user avatar
1 vote
1 answer
77 views

let $L$ be a bounded distributive lattice with dual space $(X:=\mathcal{I}_p(L), \subseteq, \tau)$, then the clopen downsets of $X$ are $X_a, a \in L$

11.22 Lemma, from B. A. Davey, H. A. Priestley, Introduction to lattices and order, let $L$ be a bounded distributive lattice with dual space $(X:=\mathcal{I}_p(L), \subseteq, \tau)$ and $X_a = \{I \...
AleVanDerBauch's user avatar
2 votes
1 answer
37 views

Need a clarification of the proof that the prime ideal space of a distributive bounded lattice is compact

11.19 Theorem, from B. A. Davey, H. A. Priestley, Introduction to lattices and order, Let $L$ be a bounded distributive lattice, then the prime ideal space $\langle \mathcal{I}_p(L); \tau \rangle$ ...
AleVanDerBauch's user avatar

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