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Sum of partition's product modulo 5 up to 41
If we define $S(n)$ as
$4=3+1=2+2=2+1+1=1+1+1+1$
$S(4)=3\cdot1+2\cdot2+2\cdot1\cdot1+1\cdot1\cdot1\cdot1=3+4+2+1=10$
$5=4+1=3+2=2+2+1=2+1+1+1=1+1+1+1+1$
$S(5)=4\cdot1+3\cdot2+2\cdot2\cdot1+2\cdot1\...
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