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1 vote
0 answers
89 views

A summation formula for number of ways $n$ identical objects can be put in $m$ identical bins

A famous counting problem is to calculate the number of ways $n$ identical objects can be put into $m$ identical bins. I know that this problem is somewhat equivalent to Partition problem. There is no ...
Fish_n_Chips's user avatar
1 vote
1 answer
114 views

summation of product of binomials coefficients over compositions

I am having trouble with this problem which arises in the context of computing lowest theoretically possible computation cost for some cryptographic primitive. Let $n$ and $a$ be positive integers ...
curioustechie's user avatar
1 vote
3 answers
223 views

Reorganising alternating sum of products of binomial coefficients

The summation $$ \sum_{k=0}^{\lfloor\frac{p}{s}\rfloor}(-1)^k {n\choose k}{p-ks+n-1\choose n-1}\quad;n > 0, s > 0 \text{ and } 0\le p\le ns, $$ with ${n\choose k}$ denoting the binomial ...
Christopher Dearlove's user avatar
2 votes
2 answers
231 views

Simplified $\sum_{n=a_1k_1+a_2k_2+\cdots+a_mk_m}\frac{(a_1+a_1+\cdots+a_m)!}{a_1!\cdot a_2!\cdots a_m!}\prod_{i=1}^m \left(f(k_i)\right)^{a_i}$

I'm studying a function of the form $$b_n=\sum_{n=a_1k_1+a_2k_2+\cdots+a_mk_m}\frac{(a_1+a_2+\cdots+a_m)!}{a_1!\cdot a_2!\cdots a_m!}\prod_{i=1}^m \left(f(k_i)\right)^{a_i}$$ Where the sum is over ...
tyobrien's user avatar
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