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2 votes
1 answer
86 views

Direct sum of free abelian group and quotient of abelian group by subgroup

I'm currently studying abelian groups in Kurosh's The Theory of Groups. I'm trying to understand the proof of the theorem: Let $B \leqq A$ be abelian groups. If $A/B \cong C$ and $C$ is a free group, ...
MathematicallyUnsound's user avatar
1 vote
0 answers
55 views

Construction of Free abelian groups on Massey Book

I am reading the book of Massey of Algebraic topology, and I am having trouble to understand this construction. Let $ S = \left\{ x_i : i\in I \right\}$. For each index $i$, let $S_i$ denote the ...
Horned Sphere's user avatar
0 votes
0 answers
61 views

Understanding "formal sum" in free abelian groups

Despite reading about formal sums and especially the last comment in this post (which seems most relevant to my question) - I still feel the need to make sure I'm not missing something: If there is a ...
Anon's user avatar
  • 1,791
0 votes
3 answers
281 views

Abelianization of free groups

I'm reading Hatcher's Algebraic Topology and I have some questions about an argument on Page 42: The abelianization of a free group is a free abelian group with basis the same set of generators, so ...
Dasheng Wang's user avatar
2 votes
1 answer
174 views

Set of homomorphisms on a free abelian group is a free abelian group.

If $G$ is a free abelian group with rank $n$, I need to show that ${\rm Hom}(G,\mathbb{Z})$, set of all homomorphisms is also free abelian group of rank $n$, My work: Since $G$ is free abelian group ...
Adam_math's user avatar
  • 319
0 votes
0 answers
57 views

Order of a quotient of a free abelian group

Let $G\subseteq \mathbb{C}$ be a free abelian group of rank $n$ and let $p$ be a prime. Then, we know that $$|G/pG|=p^n$$ and in fact for this we don't even need $p$ to be a prime. Suppose now that ...
MarkG99's user avatar
-1 votes
2 answers
165 views

Is $\mathbb{Z_5}$a free abelian group ? Yes/No [closed]

Is $\mathbb{Z_5}$ a free abelian group ? My attempt: I think $\mathbb{Z_5}$ is free abelian group By the definition of free abelian group $X$ generates $G$, and $n_1x_1 +n_2x_2 +\dots+n_rx_r=0$ ...
jasmine's user avatar
  • 14.6k
1 vote
0 answers
142 views

In $F=F^{ab}(A)$, define $f\sim f'$ if and only if $f-f'=2g$ for some $g\in F$. Show $F/\sim$ is finite if and only if $A$ is finite.

this is a question from Aluffi's Algebra: Chapter 0, Exercise II.5.10. The full question is the following: Given a free abelian group over a set $A$, denoted $F=F^{ab}(A)$, we define an equivalence ...
iceberg56's user avatar
1 vote
1 answer
81 views

Defining a map on a subgroup of a free group

Given a set $S$, we write $G(S)$ for the free abelian group on the basis $S$. Given a subset $T\subseteq S$, let $H$ be the subgroup of $G(S)$ generated by $T$. I wonder if the following is true: Can ...
user avatar
0 votes
2 answers
64 views

Basis for a free abelian group $F(X)/F(X)'$

Let $|X|=n,$ prove that $F(X)/F(x)'$ is a free abelian group of rank $|X|$. For the rank prove and use that $\{xF(X)' : x \in X \}$ is a basis for $F(X)/F(X)'$. The abelian part is because in a group $...
George's user avatar
  • 549
2 votes
1 answer
126 views

Rank of a free group times a free abelian group.

I know that the rank (i.e. minimal number of generators) of the product $\mathbb{Z}\times F_2$, of the infinite cyclic and free group on two generators, is three, but the only argument I could quickly ...
lemon314's user avatar
  • 243
1 vote
1 answer
120 views

What is the free abelian group on $\mathbb{N}$?

I learnt that the free abelian group on a set $X$ is the group $(\operatorname{Hom}(X, \mathbb{Z}), +)$. Okay, this sounds all right, but I also know the famous result that $\mathbb{Z}^{\mathbb{N}}$ ...
JustAnAmateur's user avatar
2 votes
4 answers
388 views

How's the 'integer lattice' or the 'direct sum' of $\mathbb{Z} \oplus \mathbb{Z}$ not a Free group?

My question is about the direct sum $\mathbb{Z} \oplus \mathbb{Z}$ which is a Free Abelian group and not a free group. The the integer lattice, or what I think is the direct sum $\mathbb{Z} \oplus \...
crecycreme's user avatar
0 votes
1 answer
108 views

Factor group of a free group

Let $F[A]$ be the free group on the generating set $A$. Let $C$ be the commutator subgroup of $F[A]$, then show that $F[A]/C$ is a free abelian group with basis $\{aC \mid a \in A\}$. It is trivial ...
Sphere's user avatar
  • 711
2 votes
1 answer
307 views

Free groups as free product of infinite cyclic groups

Let $S$ be an arbitrary set (countable or uncountable). It is clear that the free abelian group generated by $S$ is isomorphic to the direct sum $$\bigoplus_{s\in S}\mathbb{Z}.$$ Is the free group ...
B.Hueber's user avatar
  • 2,876

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