Skip to main content

All Questions

5 votes
0 answers
101 views

Zeta Lerch function. Proof of functional equation.

so I'm trying to prove the functional equation of Lerch Zeta, through the Hankel contour and Residue theorem, did the following. In the article "Note sur la function" by Mr. Mathias Lerch, a ...
Nightmare Integral's user avatar
0 votes
1 answer
99 views

can we have a Taylor series expansion of the function $\frac{1}{\zeta(s)}$?

can we have a Taylor series expansion of the function $\frac{1}{\zeta(s)}$at $s=1$? if so how can we determine the radius of convergence of this expansion without assuming the truth of the riemann ...
Haidara's user avatar
  • 43
1 vote
0 answers
28 views

Are there some natural bijections between general Dirichlet series and power series?

The theory of general Dirichlet series and the theory of power theory have some analogs: The abscissa, line and half-plane of convergence of a Dirichlet series are analogous to radius, boundary and ...
Xuexing Lu's user avatar
1 vote
2 answers
153 views

Proving $\prod_{n=0}^{\infty}\left(1+\frac{x}{a^n}\right)=\sum_{n=0}^{\infty}\frac{(ax)^n}{\prod_{k=1}^{n}(a^k-1)}$

By trying to prove that Riemann's Zeta function is analytically expendable to the whole plane with one pole, I went aside and noticed this identity about formal power series (which are obviously ...
donaastor's user avatar
  • 1,697
0 votes
1 answer
187 views

Dirichlet L functions [closed]

I would like to know more special Dirichlet L functions (like Zeta function for instace). Despite Zeta, Beta, Eta, Lambda and Hurwitz zeta are there more special Dirichlet L functions? I went to the ...
Mr. N's user avatar
  • 516
1 vote
0 answers
32 views

Generalization of convolution operation? [duplicate]

In integral transforms, convolution is defined by $$ (f*g)(t)=\int_{-\infty}^\infty f(\tau)g(t-\tau)\mathrm d\tau $$ satisfying the commutative, associative property, and $$ \mathcal F\{f*g\}=\mathcal ...
TravorLZH's user avatar
  • 7,193
1 vote
0 answers
55 views

Dirichlet Theorem Expansion to power series

I am nearly complete in my understanding of this beautiful theorem of Dirichlet. On page 34 of Davenports book (Multiplicative number theory) the following breakdown is present and I do not understand ...
gnarm's user avatar
  • 81
1 vote
1 answer
83 views

Are all series in the elementary Ramanujan class R = 1 non-summable by analytic continuation of Dirichlet series?

We say that a series $\sum_{n=1}^\infty a_n$ and the corresponding power series $f(x)=\sum_{n=1}^\infty a_nx^n$ belong to the Ramanujan class $R=1$ if $g(x)=f(x)-f(x^2)$ is Abel summable at $x=1$ (...
user avatar
2 votes
1 answer
354 views

Does the Abel sum 1 - 1 + 1 - 1 + ... = 1/2 imply $\eta(0)=1/2$?

If $\sum_{n=1}^\infty a_n$ is Abel summable to $A$, then necessarily $\sum_{n=1}^\infty a_n n^{-s}$ has a finite abscissa of convergence and can be analytically continued to a function $F(s)$ on a ...
user avatar
0 votes
1 answer
79 views

What's the function that is related to 3 as the Riemann zeta function is related to 2?

For $f(x)=\sum_{n=0}^\infty a_n x^n$, a real number $R\neq 1$, $g(x)=f(x)-Rf(x^2)$ Abel summable at $x=1$, $g(1)=\lim_{x\to 1^-} g(x)$, the elementary Ramanujan sum of $f(x)$ at $x=1$ is defined by $f(...
user avatar
1 vote
1 answer
119 views

Translations AND dilations of infinite series

Sometimes, when working with infinite series, it's useful to add "dilated" or "translated" versions of the infinite series, term by term, back to the original. There are ways of making this rigorous ...
Mike Battaglia's user avatar
6 votes
1 answer
287 views

"Reduction of Dirichlet series into power series"

In a paper of Riemann, he states to following formal identity. If $f(s)=\sum\limits_{k=1}^{\infty}\frac{a_k}{k^s}$ and $F(x)=\sum\limits_{k=1}^{\infty}a_kx^k$ then $$\Gamma(s)f(s)=\int\limits_{0}^{\...
Elie Bergman's user avatar
  • 3,967
4 votes
1 answer
213 views

A numeral system built around Dirichlet series, by analogy of how positional numeral systems are built around power series?

For any natural number and chosen base p, the number admits a unique expression of the form $a_np^n + ... + a_2p^2 + a_1p^1 + a_0$, where $a_k < p$ for all k. This property is effectively what ...
Mike Battaglia's user avatar