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0 votes
1 answer
57 views

In complex number system, sin z and cos z are unbounded and periodic. But they are continuous also. How can that be possible?

I know that a continuous periodic function must be bounded because if a function is continuous and periodic, its graph will have to turn at certain points to reattain the values and hence, it cannot ...
Ria Talwar 's user avatar
5 votes
6 answers
628 views

What is $\sqrt{-1}$? circular reasoning defining $i$.

I am reading complex analysis by Gamelin and I am having trouble understanding the square root function. The principal branch of $\sqrt{z}$ ( $f_1(z)$ ) is defined as $|z|^{\frac 1 2} e^{\frac{i \...
pie's user avatar
  • 6,620
0 votes
2 answers
128 views

As a matter of fact, it is impossible to find a continuous $f$ such that $(f(z))^2=z$ for all $z$. ("Calculus Fourth Edition" by Michael Spivak.)

As a matter of fact, it is impossible to find a continuous $f$ such that $(f(z))^2=z$ for all $z$. In fact, it is even impossible for $f(z)$ to be defined for all $z$ with $|z|=1$. To prove this by ...
佐武五郎's user avatar
  • 1,138
0 votes
1 answer
66 views

Prove that $f(z)=\int_0 ^1 t^z dt$ is continuous

Let $$f(z)=\int_0 ^1 t^z dt.$$ Prove that $f$ is holomorphic on $\{\Re(z)>-1\}$. My attempt: First notice that $$|t^z|=|e^{z\log(t)}|=e^{\Re(z\log(t))}=e^{\log(t)\Re(z)}=t^{\Re(z)},$$ and thus $$\...
shp's user avatar
  • 146
2 votes
0 answers
50 views

Surface integral of a complex Log function

I am trying to calculate the surface integral of a complex Log function i.e. $$ \int\int_{|z|<1}{Log(x+i y-(x_0+iy_0)))dxdy}$$ where $z=x+iy$ and $x_0,y_0 \in \mathbb{R}$ . I know that for analytic ...
O.s.'s user avatar
  • 21
2 votes
1 answer
218 views

Continuity of $\text{Im}\frac{z}{z-1},\frac{\text{Re }z}{z},\text{Re }z^2,\frac{z\text{Re }z}{\left|z\right|}$

Find the set of points for which the given functions are continuous on that points. $\text{Im}\frac{z}{z-1}$ $\frac{\text{Re }z}{z}$ $\text{Re }z^2$ $\frac{z\text{Re }z}{\left|z\right|}$ My ...
user1040538's user avatar
0 votes
1 answer
59 views

Continuity of a complex variable function.

Let $$ f(x)= \left\{ \begin{array}{lcc} \frac{z^3-1}{z^2+z+1} & if & |z| \neq 1 \\ \\ \frac{-1+i\sqrt{3}}{2} & if & |z|=1 \\ \end{array} \...
Nick_W's user avatar
  • 769
4 votes
0 answers
106 views

Do both real and imaginary roots of a cubic equation need to continuous?

I have a cubic equation: $X^3-UX^2-KX-L=0$ (1) with $X=1-E+U$, $K=4(1-\gamma^2-\lambda^2)$, $L=4\gamma^2U$. I solve Eq. (1) for the variable $E$ numerically for $U=2$ and different sets of parameter $\...
hbaromega's user avatar
  • 141
0 votes
2 answers
1k views

Prove that $f(z)$ is not continuous at $z=i$ where $f(z)=\frac{3z^4 -2z^3 +8z^2 -2z +5}{z-i}$

I tried to simplify it $$f(z)=\frac{3z^4 -2z^3 +8z^2 -2z +5}{z-i}$$ $$f(z)=\frac{{3z^2 -2z +5}{z^2+1}}{z-i}$$ $$f(z)=\frac{(3z^2 -2z +5)(z+i)(z-i)}{z-i}$$ $$f(z)=(3z^2-2z+5)(z+i)$$ How to prove that ...
yesiam's user avatar
  • 1
1 vote
1 answer
29 views

Continuity of Complex Function of Two Functions Dependent of Re(z)

I believe this function is continuous at $0$ and hence is a continuous function. It's continuous if $\lim_{z \rightarrow 0^-}\bar{z} = 0$, is that right? If so, how do I prove that that's the limit? ...
underdisplayname's user avatar
1 vote
2 answers
118 views

If $f$ is a mapping from $\overline{B_1(0)}$ to itself that is continuous and analytic, prove that $f$ has a fixed point.

I am new to this but I kept on looking answer about this problem Suppose $\displaystyle{f: \overline{B_1(0)} \rightarrow \overline{B_1(0)}}$ is continuous and $f$ is analytic in $\displaystyle{B_1(0)}$...
Jaycee Emm Yu's user avatar
1 vote
2 answers
96 views

Show there exists $z \in \mathbb{U}$ such that $\prod_{k=1}^n (z - a_k) \in \mathbb{U}$

The exercise Let $n\geq 3$ and $a_1, \dots, a_n \in \mathbb{U}$. Show there exists $z \in \mathbb{U}$ such that $\prod_{k=1}^n (z - a_k) \in \mathbb{U}$. My try Writing $z = e^{i \theta}$ and $a_k = e^...
Contestosis's user avatar
  • 1,214
1 vote
2 answers
634 views

Why is the argument function defined in Complex Analysis discontinuous?

I've been working through Spivak's Calculus and I'm currently working through Ch. 26 on Complex Functions. One of the functions they define is the argument function. Recall that the argument of a ...
D.C. the III's user avatar
  • 5,659
1 vote
1 answer
69 views

How to prove that the n-th root is not continuous using the Fundamental Group

I need to prove that the function $g:\mathbb{C}^∗ \rightarrow \mathbb{C}^*$ such that $(g(z))^n=z$ is not continuous using the fundamental group. I tried to use the argument in the question: How to ...
Sergio's user avatar
  • 25
1 vote
1 answer
199 views

How to prove that the complex logarithm is not continuous using the Fundamental Group

I need to prove that the function $f:\mathbb{C^*} \rightarrow \mathbb{C} ; \exp{(f(z))} = z$ is not continuous using the fundamental group. I´ve found this Does every continuous map induce a ...
Hojas's user avatar
  • 113

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