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3 votes
1 answer
70 views

Complex analysis, Ian Stewart Exercise 4.7.5: Proving $\sqrt{z}$ is continuous on $\mathbb{C}\setminus\{x\leq0\}$

This is exercise 4.7.5 in Ian Stewart's "Complex Analysis (The Hitch Hiker’s Guide to the Plane)": Let $C_{\pi} =\{z\in\mathbb{C}:z\neq x\in\mathbb{R},x\leq0\}$ be the 'cut plane' with the ...
HIH's user avatar
  • 451
0 votes
0 answers
78 views

Why does this show Log can't be extended to whole $\mathbb{C}^*$

Why does the following show Log can't be extended to whole $\mathbb{C}^*$? Here's another proof which I think I understand, though I'm not sure what's the connection between the two proofs: I ...
HIH's user avatar
  • 451
2 votes
1 answer
166 views

How misleading is it to regard $i$ as *the* square root of $-1$?

Many mathematicians regard writing $i=\sqrt{-1}$ as at best an abuse of notation, and at worst simply incorrect. This is because every non-zero complex number has two square roots, and there is no ...
user avatar
1 vote
1 answer
1k views

on the (double) discontinuity of dilogarithm along a branch cut

Define the function $$Li_s(z)=\sum_{k=1}^\infty \frac{z^k}{k^s}$$ for |z|<1. Let's focus on $s=2$. It can be extended to a holomorphic function on $\mathbb C \setminus [1,\infty)$ $$Li_2(z)= -\...
jj_p's user avatar
  • 2,390
1 vote
1 answer
279 views

How to define Square Root

I'm trying to understand how to define the square root of a complex function "globally". Let's say we have some function from some set $X$ onto $\mathbb{C} - \{0\}$: $$ f:X\to\mathbb{C}-\{0\} $$ and ...
PPR's user avatar
  • 1,116
1 vote
2 answers
476 views

Is discontinuity along a line equivalent to branch cut?

Suppose I claim the analytic function $f(z)$ has a branch cut along the positive real line, how would one go on to prove this? Is it sufficient to prove that $f(z)$ is discontinuous across this line? ...
Schwarz's user avatar
  • 71