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2 votes
1 answer
176 views

Integral representation of Bell Polynomial?

From Wolfram Alpha: https://functions.wolfram.com/IntegerFunctions/BellB/07/01/0001/, we have an integral representation for Bell numbers as: $B_n = \frac{2n!}{\pi e} \displaystyle{\int_{0}^{\pi}} e^{...
BBadman's user avatar
  • 317
2 votes
1 answer
313 views

Extension of the Multivariate Faa di bruno's formula with more than two composite functions

The Faa di bruno formula for one variable (Wikipedia) is The combinatorial forms in terms of bell polynomials are also included Similarly, the multivariate formula (Wikipedia) is expressed ...
Kabir Munjal's user avatar
2 votes
1 answer
240 views

prove for bell number using induction on n [duplicate]

hi guys I have to prove this equality $$B_n=e^{-1}\sum_{k=0}^{\infty}\frac{k^n}{k!},$$ that is called bell equality only using induction on $n$ . How can i do this? I have tried by substituting the ...
Alfredo Cozzolini's user avatar
6 votes
3 answers
221 views

Compact formula for the $n$th derivative of $f\left(\sqrt{x+1}\right)$?

I'm interested in a general formula for $$\frac{d^n}{dx^n}\Big[f\left(\sqrt{x+1}\right)\Big].$$ In particular, Fàa di Bruno's formula gives $$\frac{d^n}{dx^n}\Big[f\left(\sqrt{x+1}\right)\Big]=\sum_{k=...
WillG's user avatar
  • 6,692
1 vote
1 answer
55 views

Alternative representation for $B_{n,k}(1!,\dots,(n-k+1)!)$

Let $B_{n,k}$ be the Exponential Bell Polynomial and $\hat {B}_{n,k}$ the Ordinary Bell Polynomial. One has the identity: $$ B_{n,k}(0!,1!,\dots,(n-k)!) = |s(n,k)|, $$ with $s(n,k)$ the Stirling ...
HolyMonk's user avatar
  • 1,135
8 votes
1 answer
763 views

Sum of Bell Polynomials of the Second Kind

A problem of interest that has come up for me recently is solving the following. $$\frac{d^{n}}{dt^{n}}e^{g(t)}$$ There is a formula for a general $n$-th order derivative of a composition as shown ...
Tucker's user avatar
  • 2,120