A cubic function has the rule $y=f(x).$ The graph of the derivative function $f'$ crosses the $x$-axis at $(2,0)$ and $(-3,0).$ The maximum value of the derivative function is $10$.
The value of $x$ for which the graph of $y=f(x)$ has a local maximum is
$\eqalign{&{\bf A.} \ \ -2 \\ &{\bf B. } \ \ 2 \\ &{\bf C. } \ \ -3 \\ &{\bf D. } \ \ 3 \\ &{\bf E. } \ \ -\dfrac12 }$
What do I do with the information "maximum value of the derivative function is $10$? Does this mean the max value of the range of $f'(x) = 10$. How do I know where this point lies on the $f'(x)$ graph?
All I know is:
- $f'(2) = 0$ which means its a stationary point for $f(x)$.
- $f'(-3) = 0$ which means its another stationary point for $f(x)$.
Very confused. Can someone please help me interpret the question, and then solve for the local maximum.
The answer given is B:2