Given ordered pairs $p_i = (x_i, y_i)$ where $x, y \in I$, find a pair $(x_o, y_o)$ where the distance between $o$ and all $p_i$ is equal.
The problem may also be imagined as trying to find the origin of a unit circle, given points that exist along its edge. I've been wracking my brain trying to figure out how.
I know that the slope may be calculated with two points as $m = \frac{y_2-y_1}{x_2-x_1}$ and further, the angle via $\theta=\arctan(m)$. I also know that where $\theta = 45^\circ, i = 2$, the origin of the circle is $(x_1, y_2),(x_2, y_1)$. I can imagine extrapolating the origin via $(x_2+((x_2-x_1)-(y_2-y_1)), y_1),x_2-x_1<y_2-y_1$. I don't think that's completely correct. The idea is to add to the coordinate with the smallest difference until the difference between the differences of both x and y is equal (create a 45 degree angle).
Anyways, thanks so much for any help. If you can, draw a picture because I find it somewhat difficult to visualize mathematics. If you don't have the chance to draw a picture, please provide a written explanation of anything you use more complex than algebra (I'm still on mathematical training wheels).