Ramsey’s Theorem:
Example:
Take a set $S$ of $n$ elements. Construct all $3$-tuples.
Color each $3$-tuple with one of $4$ colors (blue, green, red, orange)
$S = \{1, 2, 3, …, n\}$
$\color\red{\fbox{1,2,3}},\color\green{\fbox{1,2,4}},\color\royalblue{\fbox{1,2,5}},\dots,\color\green{\fbox{4,7,13}}.$
We want a monochromatic subset $T$ of $S$ of size $20.$
$T = \{4, 7, 13, 15, 21, 38, …\},|T| = 20.$
$\color\green{\fbox{4,7,13}},\color\green{\fbox{4,7,15}},\dots$
Ramsey
: Such a $T$ always exists if $n$ is large enough.
Theorem Statement
: For every $m, c,$ and $k$ there exists $n$ such that, if you take a set of size $n$ and color the $m$-tuples with $c$ colors, there will always exist a monochromatic subset of size $k$.
Given:
$m$ – tuple size
$c$ – number of colors
$k$ – desired size of monochromatic subset
There exists: $n$ – size of original set
Proof of Ramsey’s Theorem
:
We want to prove the theorem for a certain $(m, c, k).$
We assume, by induction on $m$, that the claim is true for $(m–1, c, k')$ for all $k'.$
Take a set $S$ of size $n,$ for $n$ large enough. Suppose we are given a $c$-coloring $K$ of the $m$-tuples of $S.$
Take $x_1\in S$. Let $T_1=S \setminus \{x_1\}.$ Color the $(m–1)$-tuples of $T_1$ according to their color with $x_1$ in $K.$ Get coloring $K_1.$
By induction assumption, there exists a subset $S_2\subseteq T_1$ all whose $(m–1)$-tuples have the same color in $K_1$.Say all red.
All $m$-tuples “$x_1$ plus $m–1$ elements of $T_1$” are red in $K.$
Color $x_1$ red. $S_2$ is large enough if $S$ is large enough.
Take $x_2\in S_2$. Let $T_2=S_2 \setminus \{x_2\}.$ Define coloring $K_2$ of $(m–1)$-tuples of $T_2$ as before.
By induction assumption, there exists $S_3\subseteq T_2$ all whose $(m–1)$-tuples have the same color in $K_2.$
Say all blue.
Color $x_2$ blue. $S_3$ is large enough if $S_2$ is large enough.
And so on…
Keep going until we have $k$ of the same color.
My question is how many steps are sufficient by PHP(pigeon hole principle)?