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I have been thinking about the possibility of representing all points in a $4$-dimensional spacetime coordinate system $\mathbb{R}^{1,4}$, as points on one line $P$ (or axis of a $1$-dimensional coordinate system $\mathbb{R}^1$).

Then if $X$ is a point on $P$, and ($ct,x,y,z$) is the corresponding point in $\mathbb{R}^{1,4}$, we must have $X=f(ct,x,y,z)$, where the values of the function $f$ must be different for all values of the $ct,x,y$ and $z$.

For example, function $f(ct,x,y,z)=ct+x+y+z$, is not possible, because, for two different inputs of ($ct,x,y,z$), one can have the same result for $f$. Similarly, $f(ct,x,y,z)=ctxyz$ also cannot work.

Is there any function $f$ that can satisfy the above mentioned required property?

Edit: I'm looking for a bijective function $f$ that takes 4 inputs and gives a unique value for each input set.

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    $\begingroup$ Yes, but it can't be made continuous so it isn't useful for anything. $\endgroup$ Commented Jun 30 at 6:39
  • $\begingroup$ I hope that such a continous function exists. But If one prove that a continuous function of these properties do not exist, then the results could still be worth studying. $\endgroup$ Commented Jun 30 at 7:31
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    $\begingroup$ The nonexistence of that (continuous, bijective) function is proven in front of our nose. A better notation would also be $\mathbb R^{1,\color{red}3}\,.$ $\endgroup$
    – Kurt G.
    Commented Jun 30 at 8:36
  • $\begingroup$ @KurtG. thank you for the reference. But still if there exists a disconnected bijective function of properties i mentioned, what would it look like? $\endgroup$ Commented Jun 30 at 9:59
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    $\begingroup$ I googled it for you. $\endgroup$
    – Kurt G.
    Commented Jun 30 at 11:28

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