Let $u=((x+y)z,y+xz,z^2+xz)$ be a vector field and $\Sigma$ be the surface $\frac{x^2}{9}+\frac{y^2}{4}+\frac{z^2}{36}=1$. Calculate $\iint_{\Sigma}(u\cdot N)dS$.
So $\text{div }u=1+3z+x$ and by using gauss theorem $\iiint_K (1+x+3z)dV=\iiint_K1dV$, by symmetry. The volume of $K$ is $\frac{4}{3}\pi*3*2*6=48\pi$ but the answer should be $8\pi$ or $-8\pi$. What is wrong here?