In the answer here, should the number of ways to pick the groups of triples, pairs and singlets from the 20 people be: $$\frac{20!}{\color{#C00}{3!^2}\,\color{#090}{2!^4}\,\color{#E90}{6!}}$$ since if you were to take this to the extreme and have 20 single people, there would be only 1 way to do it, which would be $$\frac{20!}{20!}$$
I would like to think it is a typo, but I want to make sure my understanding is correct.