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I have been staring at this problem for longer than I would like to admit.

I am trying to determine the path of a light ray from an object that is reflected from two plane mirrors and into the aperture of a pinhole camera. I have sketched the arrangement here.

  • The ray starts at the known point D (the object)
  • Then is reflected from the first plane mirror at unknown point C with unknown angle of incidence and reflection $\theta_C$
  • Then is reflected from the second plane mirror at unknown point B with unknown angle of incidence and reflection $\theta_B$
  • Finally the ray ends the known point A (the pinhole)

The point C lies on the surface of the first mirror, given by the known points G and H, and the point B lies on the surface of the second mirror, given by the known points E and F. To determine the light path, we need to find the two unknown points C and B.

To approach this problem, I have tried to solve for $\theta_C$ and $\theta_B$ by dividing my previous sketch into three (see here). From each sketch I find the following:

  1. $\theta_C=\pi-\widehat{CHD}^*-\widehat{HDC}$
  2. $\theta_B-\theta_C=\pi-\widehat{CGE}^*-\widehat{GEB}^*$
  3. $\theta_B=\pi-\widehat{BAE}-\widehat{AEB}^*$

where I have indicated known angles with a $^*$. But in these three equations, I have four unknowns. So I am missing something. I would be very grateful if someone could take the time to help me find the missing piece. Thank you.

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    $\begingroup$ Reflect point $D$ abour the first mirror, and reflect point $A$ about the second mirror. The images of reflection $D'$ and $A'$ are along the path of the ray from the first mirror to the second mirror. This way, by intersecting the line connecting $D'$ and $A'$ with the lines defining the two mirrors, you obtain the reflection points and the incidence angles on the two mirrors. $\endgroup$
    – Quadrics
    Commented Sep 9, 2023 at 17:42
  • $\begingroup$ Perfect, thank you. $\endgroup$
    – jon_burns
    Commented Sep 10, 2023 at 14:55

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