If we write down the digits of the $33$ rd Fermat number $$F_{33}=2^{2^{33}}+1$$ in base $10$ in reverse order , the resulting number should , considering its magnitude , be composite.
But can we search for a prime factor WITHOUT actually calculating $F_{33}$ ? $F_{33}$ begins with a $9$ , so there is no obvious prime factor of the reversed number. Can I , for example , determine whether the reverse of $F_{33}$ is divisible by $7$ ?