I am reading a proof over 4.2 in Suzuki group theory I and can't make sense of some parts.
I will just type the proof and then say what my query is.
Statement
Let $(W,S)$ be a Coxeter system. Let $T$ be the set of all elements of $W$ that are conjugate to some generator $s \in S$. Let $X=\{\pm 1 \} \times T$.
For a sequence $\mathfrak{s}=(s_1,\dotsc,s_q)$ define $\mathfrak{t}$ to be the sequence $(t_1,\dotsc,t_q)$ where $$t_i = (s_1\dotsm s_{i-1}) s_i (s_1\dotsm s_{i-1})^{-1} \in T. $$
For any $t \in T$ let $n(\mathfrak{s}, t)$ be the number of indices $j$ such that $t_j=t$.
Define $\eta(\mathfrak{s}, t)=(-1)^{n(\mathfrak{s},t)}$.
Define $U:S \rightarrow \operatorname{sym}(X) $, $s \mapsto U_s $ where $$U_s(\epsilon, t)=(\pm \epsilon, sts) $$ where the signature of the right side of the equation is negative only when $s=t$.
Then the mapping $U $ can be extended to a homomorphism from all of $W$ to $\operatorname{sym}(X)$.
Proof
We have $U_s^2=1$ and so $U_s$ is a permutation of $X$. We just need to show that this map $U$ preserves the relations of the group.
Let $s, s' \in S$ and let $m$ be the order of $ss'$. Then for any $k<m $ we get $$(U_{s'}U_s)^k(\epsilon, t) = (\pm \epsilon, (ss')^{-k}t(ss')^k).$$
Now the sign of $\epsilon $ changes at $k+1$ if and only if $(ss')^{-k}t(ss')^k=s$ or $(ss')^{-k}t(ss')^k = ss's$. (*) In these cases we have either $t=(ss')^{2k}s $ or $t=(ss')^{2k+1}s$. (**) If $t=(ss')^l s $ for some $l < m $ then $t=(ss')^{l+m}s$. So a change of sign occurs twice. Thus $(U_{s'}U_s)^m=1 $ and the mapping preserves the defining relations.
Queries
(*) Firstly, how has he gone from $(ss')^{-k}t(ss')^k = s$ to $t=(ss')^{2k}s $, when surely it should be $t=(ss')^k s (ss')^{-k} $?
(**) Secondly, what does he mean by “the change of sign occurs twice” and how does this imply that $(U_{s'}U_s)^m=1$?
Any help would be greatly appreciated.