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In elementary textbooks on differential calculus, the notion of derivative number at, say, $x=a$ (i.e. $f'(a)$) is sometimes introduced via a parallelism between the analytic process and the geometric process, saying: while the difference quotient ($ \frac { f(a+h) - f(a)} { h} $) goes to a determinate limit (as $h$ goes to $0$), the straight line passing through $(a, f(a))$ and $(a+h, f(a+h))$ tends to a " limiting position", namely the tangent line to the graph of function $ f$ at point $(a, f(a))$.

Of course, this approach is intuitive, and using a graphing calculator we "see" that the line defined by $ y-f(a) = f'(a) ( x-a)$ is tangent to the graph of function $f$.

Here we seem to face an alternative: (1) either the tangent is defined as the line satisfying the above equation ( and in that case my question is pointless), or (2) we have a concept of tangent line that is independent from differential calculus , in such a way that the claim "the line passing through $(a, f(a))$ and having a slope equal to $f'(a)$ is tangent to the graph of $f$" has a substantial content.

In short: is it possible to prove, as an informative (and not simply definitional) claim that the line defined by $ y-f(a) = f'(a) (x-a)$ is the tangent to the graph of $f$ passing through $(a, f(a)$? And if so, which concept of "tangent " can be used to this effect?

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    $\begingroup$ "How do we know that the derivative number is actually the slope of the tangent line." Because that is how the tangent line is defined. $\endgroup$
    – Xander Henderson
    Commented Jul 30, 2023 at 16:31
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    $\begingroup$ Related: math.stackexchange.com/q/4028997/42969 $\endgroup$
    – Martin R
    Commented Jul 30, 2023 at 16:36
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    $\begingroup$ And, as @MartinR points out, there are other ways of talking about tangency, but most of these are either non-standard (like the one I presented above), or more sophisticated, and generally require building a lot more theory before you can get to a definition. (And you aren't really going to get very far away from some notion of "derivative", anyway). $\endgroup$
    – Xander Henderson
    Commented Jul 30, 2023 at 16:39
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    $\begingroup$ @LBE What line is "tangent" to $x \mapsto x^2 \sin(1/x)$ at zero? $\endgroup$
    – Xander Henderson
    Commented Jul 30, 2023 at 16:42
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    $\begingroup$ @LBE: Xander's function is still a counterexample -- the intersection of the graph with the tangent at $0$ contains infinitely many isolated points for any neighbourhood $U$ of $(0,0)$. $\endgroup$
    – TonyK
    Commented Jul 30, 2023 at 16:45

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