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Why is convergence in distribution defined in terms of "weak" convergence in the law?

Intuitively, (at least at a literal level) convergence in distribution of $(X_n)_n$ sequence of Borel random variables should imply "convergence" in the Law of these random variables. If I were to guess the definition of Convergence in Distribution before studying it, I would probably say:

$X_n \stackrel{d}{\to} X$ if $\mu_{X_n}(S) \to \mu_X(S)$ for all Borel $S$.

This is obviously a lot stronger than the actual definition of Convergence in Distribution. But what would be the problem if we defined it this way?

Here is the definition of Convergence in Distribution introduced in my Probability class:

Definition of Convergence in Distribution:

Fix $(X_m)_{m = 1} ^\infty$ of random vectors in $\mathbb{R}^n$(they may live on different probability spaces) and $X$ random vector in $\mathbb{R}^n$. Then $X_n \stackrel{d}{\to} X$ in distribution if $\mu_{X_n} \stackrel{w}{\to} \mu_X$.

Definition of Weak Convergence in probability:

$\mu_{X_n} \stackrel{w}{\to} \mu_X$ means $\int_\mathbb{R^n} h \,d\mu_{X_n} \to \int_\mathbb{R^n} h \,d\mu_X$ for all $h: \mathbb{R}^n \to \mathbb{R}$ continuous and bounded.

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    $\begingroup$ your first intuitive definition is equivalent to the definition of weak convergence you give below if you replace "all Borel $S$" with "all continuity sets $S$ of $\mu_X$" by the Portmanteau theorem $\endgroup$
    – G. Gare
    Commented Jul 17, 2023 at 14:29
  • $\begingroup$ @G.Gare Yes. This is again a lot weaker than what I intuitively thought convergence in distribution is. $\endgroup$
    – Partial T
    Commented Jul 17, 2023 at 14:40
  • $\begingroup$ For example, CLT would stop working for non-continuous variables. $\endgroup$
    – mihaild
    Commented Jul 17, 2023 at 15:46
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    $\begingroup$ Take a normal distribution with variance $\epsilon$. As $\epsilon\to 0$ it is intuitively clear that this should converge in distribution to the $0$ random variable. Now take your borel set $B$ to be $\{0\}$ and you see that the convergence would fail under your definition. $\endgroup$
    – shalop
    Commented Jul 17, 2023 at 15:52

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