This is related to a deleted question which asked about the complex series
$$S_u = \sum\limits_{n=1}^{\infty}e^{-iun}\frac{\sin(n)}{n} $$
All the terms are real when $u$ is a multiple of $\pi$, and when it is an even multiple this gives $S_0=\sum\limits_{n=1}^{\infty} \frac{\sin(n)}{n}=\frac{\pi-1}{2}$, while if it is an odd multiple it gives $S_\pi=\sum\limits_{n=1}^{\infty} (-1)^n\frac{\sin(n)}{n}=-\frac{1}{2}$, each with $O(\frac1n)$ convergence.
The surprising result is what happens for other values of $u$. My empirical investigations suggest that:
- you get conditional convergence to a complex value except when $u=2k\pi \pm 1$;
- $Re(S_u) = \frac{\pi-1}{2}$ when $2k \pi -1 < u <2k \pi +1$;
- $Re(S_u) = -\frac{1}{2}$ when $2k \pi +1 < u <2(k+1) \pi -1$;
- there is no convergence when $u=2k\pi \pm 1$ since the imaginary parts of the partial sums diverge, but the real parts of the partial sums converge on $\frac{\pi-2}{4}$, halfway between the other two values.
My questions here are why the real part of $S_u$ only takes two (or three) values while the imaginary part can take any value, and why one of the real values is in a sense more common than the other real value.
The answer to why one value is in a sense more common may be that the two values are different in magnitude but their average over $[0,2\pi]$ is $0$.
To illustrate this, here is the real part of the sum plotted against $u$ with $u \in [-2\pi,2\pi]$
and then the imaginary part of the sum plotted against $u$