There are two decks, one with $8$ red cards and $2$ black cards, and one with $2$ red and $8$ black cards. Let us call the first deck the red, and the second the black deck. Any of the two decks is chosen with probability $1/2$. Once that has been done, there are $3$ players who get to see, each individually, one random card of the deck. In order to decide that the deck was black, the players must unanimously vote black. In all other cases, the result is red. Let us assume that players are non-strategic (i.e., follow their private signals).
- What is the probability that the players decide black but the deck is red?
- What is the probability that the players decide black?
- Suppose the players have decided black. What is the probability that the deck is really black?
I came up with the following probabilities:
- $P\text{(red deck | red card)}=P\text{(black deck | black card)}= 8/10$
- $P\text{(black deck | red card)} = P\text{(red deck | black card)} = 2/10$
- $P\text{(red deck)} = P\text{(black deck)} = 1/2$
Then for question 1, I think the answer is $$P\text{(red deck | black card)}^3 = 1/125.$$ But I have no idea how the approach question 2 and 3. Anybody has an idea?