If it is assumed that all (52C5) poker hands are equally likely, what is the probability of being dealt two pairs? (This occurs when the cards have denominations a, a, b, b, c, where a, b, and c are all distinct.
Here I am not getting why can't I solve the question as
(13C1)(4C2)(12C1)(4C2)(11C1)(4C1)
the actual answer is (13C2)(4C2)(4C2)(11C1)(4C1)