How exactly would one generalize the area of a kite inscribed within a circle? Through a lot of calculation, which I do think was actually way more complicated then required, using various trigonometric functions, chords, amongst other things, I found that the area in a unit circle would be $\sqrt{3}$. But how exactly would this be generalized?
I am thinking that one would draw a line $r$ to the centre of a circle from the edge, and draw a line across the entire circle. Draw a line starting at the point a of the original line, and go down perpendicular to the central line. Then connect all the points which hit the edges to eachother. Creating a kite.
This should allow one to find an isosceles triangle with the hypotenuses being $r$, with a height of $r$ thus the base can be $r\sqrt{3}$. This should be the side of a larger triangle, which is actually an equilateral, which would have area calculated by $\dfrac{\sqrt{3}}r r(\sqrt{3})^2$, or $\sqrt{3} × 3r^2$.
The second can be found by finding how two other cords, can make up another equilateral, showing that the hypotenuses of the bottom triangles are actually equal to r, thus it is an isosceles with the side lengths of $r$ and base of $r \sqrt{3}$.
However, we need to find the height with $(\sqrt{3}/2) × (r \sqrt{3})$ or $3r/2$, making the height of the smaller triangle $r/2$, thus the area is $\sqrt{3} r^2$.
Thus the generalized formula should be $r^2\sqrt{3}$
This should be correct, but I am open to people pointing out me messing up or overcomplicating this formula.
![](https://cdn.statically.io/img/i.sstatic.net/5GAAI.png)
Noticed the small gap, that is not supposed to be there, I just suck at editing images, imagine it touches the central line.