(I want to clear out the fact that I'm no professional mathematician. Please feel free to correct me if needed. I have no mathematical background. I am 13 years old, this question is originated from pure math curiosity)
Let $\mu$ be any number greater than zero, such that $N_d^{\mu}$ is a natural number.
Let $N_d$ be any natural number with $d$ divisors. $N_d$ has to be a prime number (or a power of prime).
Is it correct to say that $N_d^{\mu}=N_{\left(d-1\right)\mu+1}$ ?
If so, why?
An small example: let $N_d = 7$. That means $d = 2$, since the number $7$ has two divisors. We can know that the result of the expression $(d-1)\mu+1$ results in the amount of divisors that $7^\mu$ has.
Let $\mu=5$ for this example.
We can know that $7^5$ (which is equal to $16807$) has $(2 - 1)5+1=6$ divisors.
And that is correct: $16807 = 1*7*49*343*2401*16807$