Question: " You have $3$ green balls, $1$ purple ball and $4$ red balls, all in a bag. What is the probability that when you (without replacement) draw $4$ balls, $3$ of them will be green and none of them will be red."
Basically, what is the probability that you draw all the green and purple balls?
Also, is this a permutation or combination question?
What I have tried: $\frac{4P4}{8P4} = \frac{1}{70}$.
Not sure if that is correct or not because it doesn't feel right. NOTE: I get the same answer if I use choose instead.