Consider any point $P$ on the unit circle centred at the origin $O(0,0)$ in $\mathbb R^2$. Let $A$ be $(-2,0)$ and $B$ be $(2,0)$ be two point on the $x$-axis and $D$ be the sum of the two distances $AP$ and $BP$. Then $D$ is maximised when $P$ is at the top (or bottom) of the circle. This is easily proven using calculus.
Can anyone produce a simple direct geometric proof of this result. Calculus seems too heavy for this?
I must admit I was initially attracted to the option where $AP$ is a tangent to the circle, but it is inferior.
For those looking for problems, allowing A and B to be positioned randomly is also quite interesting and specialises to the above.
geometry
if that's what you are looking for. $\endgroup$