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It is well known that a finite set of $n$ points cannot form more than

$$\bigg\lfloor \frac{n(n-3)}{6} \bigg\rfloor+1 $$

lines that include $3$ points. Would this result still hold if we assume that the set $P$ of $n$ points has some sort of central symmetry i.e. $k$-fold symmetry for some $k\in \mathbb{N}$? Or would the upper bound be smaller?

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