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$$(A\land B \lor C) \land (B \lor \lnot C)$$

I know how to create the truth table and Karnaugh map of a logic expression. But I couldn't find exactly how to calculate the simplified CNF of it using the Karnaugh map.

I want to know, for CNF we have to use values $1$ or values $0$ in Karnaugh map?

Instead of an answer I want an explanation about it (a brief explanation about CNF would be great)

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  • $\begingroup$ Karnaugh map always gives the simplified DNF, but not always give the simplified CNF. $\endgroup$
    – Ethan
    Commented Jul 25, 2020 at 19:39

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