Tangents are drawn to circle $x^2+y^2-6x-4y-11=0$ from point $P(1,8)$ touching circle at $A$ and $B$. Let there be a circle whose radius passes through point of intersection of circles $x^2+y^2-2x-6y+6=0$ and $x^2+y^2+2x-6y+6=0$ and intersect the circumcircle of $PAB$ orthogonally. Find minimum radius of such a circle.
My attempt Circumcircle would be $(x-1)(x-3)+(y-2)(y-8)=0$ and centre would lie on radical axis of the given circles ie $x=0$ . therefore equation of circle will be $x^2+y^2+2fx+c=0$. Applying orthogonality condition , $c=-19-10f$ .
I am unable to find minimum radius .
Please suggest any ways to minimise the radius or any better solution if possible .