Let $\mathbb{R}_+ = [0, \infty)$. I'm looking for a family $\mathcal{U}$ of $2^\mathfrak{c}$ subsets of $\mathbb{R}_+$, such that any member of $\mathcal{U}$ is unbounded in $\mathbb{R}_+$, but the intersection of any two members of $\mathcal{U}$ is bounded. Does such family exists?
It would also be nice if every member $X$ of $\mathcal{U}$ satisfied $|X \cap [n, \infty)| = \mathfrak{c}$ for all natural $n$.
The idea behind the problem is that I obviously cannot have $2^\mathfrak{c}$ disjoint subsets of $\mathbb{R}_+$, but I want the non-disjointness to be packed in a bounded segment. It seems like it should be possible, as a bounded segment of $\mathbb{R}_+$ doesn't look much different from an unbounded segment, from a set-theoretical point of view.