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I think that I understand that if I parameterize $y=x\,$ I can write it as $f(t)=(t,t)\,$. So I'm assigning position vectors (coming from the origin) to the point $(t_0,t_0)$ for $t=t_0$. So I can say that that a vector valued function takes a scalar parameter and assign to a vector in $R^n$. And if a $(x,y)$ is going from $R^2$ to $R^n$, it is a vector field, because for each position vector I'm associating a vector ? (instead of each scalar $t$)

I'm confused because if vector valued functions can be going from $R^2$ to $R^2$ isn't it just like a vector field? (for each vector position I receive another vector in that point).

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  • $\begingroup$ By "vector field" we usually mean a function $\mathbb{R}^n\to\mathbb{R}^n$ (or $U\to\mathbb{R}^n$ for some subset $U\subset\mathbb{R}^n$). In particular, the domain and codomain have the same dimension; we think of the input as a point and the output as a vector emanating from that point. But this perspective is secretly using the natural affine connection on $\mathbb{R}^n$. A vector field is really a section of the tangent bundle of a smooth manifold: i.e., a function that takes in a point $p$ in a smooth manifold $M$ and returns a vector in $V_p$, the fiber over $p$. $\endgroup$ Commented Sep 30, 2016 at 20:54

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Sure. If you are in a region $U \subset \mathbb{R}^n$ a vector field on $U$ is a vector valued function on $U$ (taking values in $\mathbb{R}^n$).

In my mind (although maybe there are different conventions) a "vector valued function" is just any function from some space to a vector space. (I'm intentionally being a bit vague by what I mean by a "space", but most reasonable subsets of $\mathbb{R}^n$ you could write down should be fine) In particular you could define a vector valued function from some region in $\mathbb{R}^3$ to $\mathbb{R}^2$ if you wanted to.

A vector field is something more specific, it is an assignment to each point a vector inside the tangent space of your space at that point. As you suggested, for some open set $U \in \mathbb{R}^2$ this is just the same as a vector valued function $U \to \mathbb{R}^2$. However if instead our space is the unit circle $S^1 = \{(x,y) |x^2+y^2 = 1 \}$ in $\mathbb{R}^2$, then a vector field on $S^1$ is a map from $S^1$ to $\mathbb{R}^2$ with the condition that the vector assigned to a given point is tangent to the circle at that point (a harder condition to meet than just being an arbitrary vector valued function).

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  • $\begingroup$ So if I parameterize a circle the vector space would be full of vectors tangent to the circle in each point of the circle? So, perpendicular to the position vectors of the vector valued function? $\endgroup$ Commented Sep 30, 2016 at 20:41
  • $\begingroup$ What do you mean by tangent space? I don't see how the vectors in a vector field have to necessarily be tangent to anything. $\endgroup$ Commented Mar 22, 2020 at 20:39

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