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If my calculations with my computer were rights, when I've consider the sequence of integers $n\geq 1$ satisfying $$\sigma(n)\mid (n(\sigma_0(n))^2),$$ where $\sigma(n)=\sum_{d\mid n}d$ is the sum of divisors function and $\sigma_0(n)=\sum_{d\mid n}1$ the number of such divisors, then such sequence starts as

1, 3, 6, 15, 28, 33, 42, 84, 91...

but I believe that such sequence isn't in The On-Line Encyclopedia of Integer Sequence.

Question. Are right my first terms? Is known such sequence in previous encyclopedia or are there references in the literature?

I've curiosity to know what's about the number of terms in the sequence for the first $10^k$ with $k=4,5,6,\cdots, N$, thats is a plot of the counting function for previous sequence.

Question. Can you provide us a graph of the counting function of such sequence for $10^N$, for a $N$ large? Thanks in advance.

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    $\begingroup$ let $f(n) = n \sigma_0(n)^2$. you have "$\sigma(n) | f(n)$ and $\sigma(m) | f(m)$, $gcd(n,m) = 1$" $\implies$ $\sigma(nm) | f(nm)$. So a question is if there are infinitely many $n$, $gcd(n,3) = 1$, $\sigma(n) | f(n)$ $\endgroup$
    – reuns
    Commented Sep 13, 2016 at 11:40
  • $\begingroup$ Welcome @user1952009 and very thanks much. Then I undertand that you prove a claim about the sequence, but from it is deduced that is a well known sequence? It was surprising to me that the sequence that I've calculated, I believe, that isn't in OEIS. Thanks one more time. $\endgroup$
    – user243301
    Commented Sep 13, 2016 at 11:41
  • $\begingroup$ part of your sequence is oeis.org/A001599 where you get additional terms by squaring your numerator $\endgroup$
    – Will Jagy
    Commented Sep 13, 2016 at 19:32

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OEIS refer to section B2 in Guy, Unsolved Problems in Number Theory, for types of "semi" perfect numbers. They do define the harmonic numbers but do not say much more. Anyway, your sequence is a superset of the harmonic numbers (named by Pomerance in 1973), also called Ore numbers.

The harmonic numbers begin $$ 1, 6, 28, 140, 270, 496, 672, 1638, 2970, 6200, 8128, 8190, 18600, 18620, 27846, 30240, 32760, 55860, 105664, $$ and are discussed at https://oeis.org/A001599

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  • $\begingroup$ Very thanks much for your answer of the first Question. I wait some days/week if some user wants type the first terms of the sequence and do a plot/graph. And of course put a name to this sequence of integers ( of his/her sequence). Thanks one more time for your attention and user1952009 for the conjecture. $\endgroup$
    – user243301
    Commented Sep 13, 2016 at 21:26

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