Q : A card from a pack of 52 cards is lost. From the remaining cards of the pack, two cards are drawn. What is the probability that they both are diamonds?
My Approach : I calculated the probability of selecting 2 diamonds when A Diamond card is lost and added it to the probability of selecting 2 diamonds when a diamond card is not lost.
P($\frac{D}{LD})$ + P($\frac{D}{NLD}$) $= \frac{^{12}C_2}{^{51}C_2} + \frac{^{13}C_2}{^{51}C_2}$
$=\frac{48}{425}$
But the answer given in the book is $\frac{1}{17}$. Where am I going wrong?