0
$\begingroup$

I try to get a closed form of the following function $f(x)$.

$a_0\left(x\right)=x$

$a_{n+1}\left(x\right) = x^{a_n\left(x\right)}$

e.g. $a_{3}\left(x\right) = x^{ \left( x^{ \left( x^x \right) } \right) }$

The function is: $f\left(x\right)=\displaystyle\sum_{k=0}^{\infty}a_{k}\left(x\right)x^{k}$

I think it is defined for $e^{-e}<x<1$, because of: https://en.wikipedia.org/wiki/Tetration#Extension_to_infinite_heights https://en.wikipedia.org/wiki/Geometric_series#Formula

Thank you for any hints

bet regards

Kevin

$\endgroup$

1 Answer 1

0
$\begingroup$

Hint: You must have $y^y = y$, where $y=\lim_{n\rightarrow\infty}{a_n(x)}$.

$\endgroup$
2
  • $\begingroup$ $y$ could be $-1$ or $1$ to solve $y^y=y$. But with your second argument $y$ must be $1$ (for $ x=1 $). Unfortunately i dont know how to use this to simplify the sum. $\endgroup$ Commented Mar 11, 2015 at 19:29
  • $\begingroup$ Additional hint: Google "generating function". $\endgroup$ Commented Mar 11, 2015 at 19:38

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .