I wanted to check with you if my reasoning to this problem was right.
Find the global maxima and minima of $f(x,y) = xy$ inside the set $A = \{ (x,y) \in \mathbb{R}^2: \frac{|xy|}{|xy|+1} \leq 1\}$.
Testing the boundary $\frac{|xy|}{|xy|+1} = 1$, we get that $0=1$. That would imply that the set $A$ doesn't have a border.
Deriving $f$:
$f_x = y$
$f_y = x$
So the only critical point is $(0,0)$, where $f(0,0) = 0$.
Now, the function that defines $A$ seems complicated to work with. So we check the second derivatives:
$Hf(x,y) = \begin{pmatrix} 0 & 1 \\ 1 & 0 \\ \end{pmatrix} \Rightarrow \det(Hf(x,y)) = -1 < 0$.
The second derivative test says that every point in $f$ is a saddle point. By that, is it correct to say that $f$ will not have global maxima or minima at $A$?