Prove that
$$\sqrt{ \frac{2x^2 - 2x + 1}{2} } \geq \frac{1}{x + \frac{1}{x}}$$for $0 < x < 1.$
I also received this hint: With the square root in the left-hand side, you may be tempted to square both sides, but this gets messy quickly. Instead, you may want to find an intermediate inequality of the form $$\sqrt{\frac{2x^2 - 2x + 1}{2}} \ge \text{something} \ge \frac{1}{x + \frac{1}{x}},$$where "something" is simple.
How should I approach this problem? Should I work backwards? I'm stuck, all solutions are greatly appreciated.