Let $a_1, a_2, b_1, b_2, c_1, c_2, d_1, d_2, e_1, e_2$ be odd integers, with $$\gcd(a_1,a_2)=\gcd(b_1,b_2)=\gcd(c_1,c_2)=\gcd(d_1,d_2)=\gcd(e_1,e_2)=1,$$ and assume $n \ge 3$ and $m \ge 1$ are integers such that $$ \frac{a_1}{2^{3(n-1)m}a_2} + \frac{b_1}{2^{3\left((n-1)m+1\right)}b_2} + \frac{c_1}{2^{3\left((n-1)m+1\right)}c_2} + \frac{d_1}{2^{3nm}d_2} + \frac{e_1}{2^{3nm}e_2} = 1. \tag{$\star$} $$
Is there a way to prove, using only the powers of $2$ in the set of denominators, that ($\star$) is impossible?