I'm really confused on how to implement the Secant Method. If the secant method is used on $f(x) = x^5 + x^3 + 3$ and if $x_{n-2} = 0$ and $x_{n-1} = 1$ what is $x_n$?
I know I need to use $x_{n+1} = x_n - \frac{x_n - x_{n-1}}{f(x_n) - f(x_{n-1})} * f(x_n)$
But I am not really sure how to even start on this problem. I Have no idea what these values are except $x_{n-1}$ I mean plugging in what I know ($x_{n-1} = 1$) I would get: $x_{n+1} = x_n - [ \frac{x_n - 1}{f(x_n) - f(1)} ] * f(x_n)$
And I know that $f(1) = (1)^5 + (1)^3 + 3 = 5$
so that would maybe change this to $x_{n+1} = x_n - [ \frac{x_n - 1}{f(x_n) - 5} ] * f(x_n)$ ? But I am still lost on what to do next.